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Answer:
Magnitude of the acceleration(g) = 9.7 meters/second²
Explanation:
Given:
Height of tower = 56 meter
Time taken = 3.4 second
Final velocity (v) = 33 meters/second
Initial velocity (u) = 0 meters/second
Find:
Magnitude of the acceleration(g)
Computation:
Using first equation of motion:
v = u + at
Magnitude of the acceleration(g)
v = u + gt
33 = 0 + g(3.4)
g = 33 / 3.4
g = 9.7 meters/second²
Magnitude of the acceleration(g) = 9.7 meters/second²
Answer:
The Class E airspace extending upward from 700 ft or more above the surface and terminating at the base of the overlying controlled airspace.
Explanation:
The Class E airspace extending upward from 700 ft or more above the surface and terminating at the base of the overlying controlled airspace is defined as transition area.
In Class E, Instrument Flight Rules aircraft are controlled by Air Traffic Controller.
In the vast majority of areas, there are enough airports and victor airways to have Class E begin at 1,200 feet above ground level (AGL). This is known as enroute Class E airspace.