Answer:
Step-by-step explanation:
Given that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water is pumped into the tank at a rate of 4 gal/min, and when the solution is well stirred, it is then pumped out at the same rate.
Let Q(t) be the quantity of salt at time t.
Q(0) = 70 pounds
Inflow of water = outflow = 4 gal/min
So resulting volume of tank at time t = 400 gallons
Rate of change of salt = inflow - outflow
= 0 - 
i.e. 
This is a variable separable equation

Use when t =0 Q = 70
A =70
So A(t) = Q(t) =
and
A(0) = Q(0) = 70 lbs.
Answer:
11 2/3 or 11.6667
Step-by-step explanation:
Hope this helps and have a great day.
Answer:
Step-by-step explanation:
<h3>Given GP</h3>
<h3>To find</h3>
<h3>Solution</h3>
<u>Substitute ar in the second equation</u>
- ar⁵= 16
- 4r⁴ = 16
- r⁴ = 4
- r = √2
<u>Then finding a₄</u>
- a₄ = a₂*r² = 4*(√2)² = 4*2= 8
Answer: 2
2x-7=11 X=9 set up the up the negative portion of solutions Set up the negative portion of the 2x - 7= - 11 x= -2 and then x = 9,-2
Step-by-step explanation: