Answer:
The energy of atomic orbitals increases as the principal quantum number, n, increases. In any atom with two or more electrons, the repulsion between the electrons makes energies of subshells with different values of l differ so that the energy of the orbitals increases within a shell in the order s < p < d < f.
Explanation:
Answer:
+1, lose, 1, 4s, 4s and 3d
Explanation:
<em>An element with the valence electron configuration 4s¹ would form a monatomic ion with a charge of </em><em>+1</em><em>. In order to form this ion, the element will </em><em>lose</em><em> </em><em>1 </em><em>electron from the </em><em>4s </em><em>subshell.</em>
The corresponding oxidation reaction is:
K ⇒ K¹⁺ + 1 e⁻
[Ar] 4s¹ ⇒ [Ar]
<em>If an element with the valence configuration 4s² 3d⁶ loses 3 electrons, these electrons would be removed from the </em><em>4s and 3d</em><em> subshell(s).</em>
The corresponding oxidation reaction is:
Fe ⇒ Fe³⁺ + 3 e⁻
[Ar] 4s² 3d⁶ ⇒ [Ar] 4s⁰ 3d⁵
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