The given question is incomplete. The complete question is:
When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.
Answer: The vant hoff factor for sodium chloride in X is 1.9
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
= freezing point constant
i = vant hoff factor = 1 ( for non electrolyte)
m= molality =

Now Depression in freezing point for sodium chloride is given by:
= Depression in freezing point
= freezing point constant
m= molality =


Thus vant hoff factor for sodium chloride in X is 1.9
<span>• Benzene has the formula of C6H<span>6 </span>whereas cyclohexane has the formula of C6H<span>12.
</span></span>
Benzene is an aromatic compound but cyclohexane is not aromatic.
Benzene is an unsaturated molecule, but cyclohexane is saturated.
<span>
Carbon atoms in the benzene ring have sp2 hybridization where carbon atoms in the cyclohexane have sp3 hybridization.</span>
Benzene has a planar structure whereas cyclohexane has chair conformations.<span>
</span>
Sissy imposter among us haha
Pretty sure non polar bc it’s equal
Answer:
no
Explanation:
Because I have lost and I dont know where is the worksheet