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katovenus [111]
3 years ago
6

How much force is needed to accelerate a toy car of mass 8 kg at 2m/s

Physics
1 answer:
atroni [7]3 years ago
4 0

Answer:

4N

Explanation:

f = ma

8kg x 2m/s = 4N

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When you stretch a spring 33 cm past its natural length, it exerts a force of 6 N. What is the spring constant of this spring?
PilotLPTM [1.2K]

The spring formula:

       Force =  - (spring constant) · (distance stretched or squashed)

          
6 N  =  - (spring constant) · (33 cm)

                   =  - (0.33 m) · (spring constant)

          Spring constant  =   - (6 N) / (0.33 m)

                                      =    - 18.18 N/meter .

The negative signs means that the spring always wants to go in the
opposite direction from where you forced it, and return to its relaxed
length.  If you stretch it, it tries to get shorter, and if you compress it,
it tries to get longer.
6 0
3 years ago
Read 2 more answers
A brick sits on the top of a hill with a gravitational potential energy of 245 J. To determine the gravitational potential of th
Bogdan [553]

Answer:

The mass of the object, its acceleration due to gravity and the distance between the top of the hill and the ground level.

Explanation:

gravitational potential energy is the energy possessed by a body under influence of gravitational force by virtue of its position.

In order to determine the gravitational potential energy of the brick, we must know the mass (m) of the brick, its acceleration due to gravity (g) since it is acting under the influence of gravitational force and the distance between the top of the hill and the ground level. (The height).

Potential energy of a body is calculated as mass × acceleration due to gravity × height.

5 0
3 years ago
HELP!!!!!!!!!!!!
ziro4ka [17]

Answer:

-4,200,000 J

Explanation:

4 0
3 years ago
A 3-kg skateboard is rolling down the sidewalk at 4 m/s when it collides with a 1-kg skateboard that was initially at rest. If t
irga5000 [103]

Answer:

2 m/s

Explanation:

Parameters given:

Mass of first skateboard, m = 3 kg

Initial speed of first skateboard, u = 4 m/s

Mass of second skateboard, M = 1 kg

Initial speed of second skateboard, U = 0 m/s

Final speed of second skateboard, V = 6 m/s

Using the principle of the conservaton of momentum, the total initial momentum is equal to the total final momentum.

Momentum is the product of mass and velocity. This implies that:

m*u + M*U = m*v + M*V

(3*4) + (1*0) = (3*v) + (1*6)

12 + 0 = 3v + 6

=> 3v = 12 - 6

3v = 6

v = 6/3 = 2 m/s

The final speed of the 3 kg skateboard is 2 m/s

8 0
4 years ago
Read 2 more answers
A 1500kg car is at rest before it accelerates when the light turns green. If it covers 45.0 meters in 15.0 seconds, what is the
lana [24]

Answer:

300N

Explanation:

Given parameters:

Mass of car  = 1500kg

Initial velocity  = 0m/s

Distance covered  = 45m

Time  = 15s

Unknown:

Net force applied  = ?

Solution:

From Newton's second law:

  Force  = mass x acceleration

  Force  = mass x \frac{v - u}{t}  

v is the final velocity

u is the initial velocity

t is the time taken

    Final velocity  = \frac{45}{15}   =3m/s

 Force  = 1500 x \frac{3 - 0}{15}   = 300N

8 0
3 years ago
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