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3 years ago

Is the magnetic field inside a toroid uniform?

Physics

1 answer:

victus00 [196]3 years ago

4 0

If I am not wrong i thinks it is in the toroid uniforms

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URGENT

Lena [83]

Just solve for a in this equation

Vf=Vi*A

7 0

3 years ago

Read 2 more answers

An egg is thrown horizontally off the top row bleachers at the Brickyard,

Ludmilka [50]

Answer:

Explanation:

Divide 30 meters by 7.5 and you´re answer is 4. This is how I would think you solve the problem

6 0

2 years ago

QUESTION 1 Linear Motion

Misha Larkins [42]

Answer:

48.51ms / 174.6 km/h

Explanation:

y = 1/2 x g x t^2 v = g x t

when y = 120m

120 = 1/2 x 9.8 x t^2

t^2 = 24.49

t = 4.95s

when t = 4.95s

v = 9.8 x 4.95

v = 48.51 m/s = 174.6 km/h

I'd say its realistic. But I don't really know that sry

3 0

2 years ago

Which describes the average velocity of an ant traveling at a constant speed

yanalaym [24]

Answer: A. The total displacement divided by the time and C. The slope of the ant's displacement vs. time graph.

Explanation:

Hi! The question seems incomplete, but I found the options on the internt:

A. The total displacement divided by the time.

B. The slope of the ant's acceleration vs. time graph.

C. The slope of the ant's displacement vs. time graph.

D. The average acceleration divided by the time.

Now, since we know the ant is travelling at a constant speed, its average velocity $V$ will be expressed by the following equation:

$V=\frac{d}{t}$

Where:

$d$ is the ant's total displacement

$t$ is the time it took to the ant to travel to the kitchen

Hence one of the correct options is: A. The total displacement divided by the time

On the other hand, this can be expressed by a displacement vs. time graph graph, where the slope of that line leads to the equation written above. So, the other correct option is: C. The slope of the ant's displacement vs. time graph.

3 0

3 years ago

Suppose a rocket ship in deep space moves with constant acceleration equal to 9.80 m/s2, which gives the illusion of normal grav

DochEvi [55]

Answer:

a) 3673469.39 seconds

b) 6.61×10¹⁴ m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0.12×3×10⁸ m/s

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

Equation of motion

$v=u+at\\\Rightarrow 0.12\times 3\times 10^8=0+9.8t\\\Rightarrow t=\frac{0.12\times 3\times 10^8}{9.8}=3673469.39\ s$

Time taken to reach 12% of light speed is 3673469.39 seconds

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{(0.12\times 3\times 10^8)^2-0^2}{2\times 9.8}\\\Rightarrow s=6.61 \times 10^{14}\ m$

The distance it would have to travel is 6.61×10¹⁴ m

7 0

3 years ago