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joja [24]
3 years ago
5

The bullet starts at rest in the gun. An 8.6 g bullet leaves the muzzle of a rifle with a speed of 430.1 m/s. What constant forc

e is exerted on the bullet while it is traveling down the 0.5 m length of the barrel of the rifle?
Physics
1 answer:
xenn [34]3 years ago
3 0

Answer:

The constant force exerted on the bullet is 1590.87 N.

Explanation:

It is given that,

Mass of the bullet, m = 8.6 g

Initial speed of the bullet, u = 0          

Final speed of the bullet, v = 430.1 m/s

We need to find the force exerted on the bullet while it is traveling down the 0.5 m length of the barrel of the rifle. Let a is the acceleration of the bullet. So,

v^2-u^2=2ad

v^2=2ad

a=\dfrac{v^2}{2d}

a=\dfrac{(430.1)^2}{2\times 0.5}

a=184986.01\ m/s^2

Let F is the force exerted. It is given by :

F=ma

F=8.6\times 10^{-3}\times 184986.01

F = 1590.87 N

So, the constant force exerted on the bullet is 1590.87 N. Hence, this is the required solution.                                                  

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