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joja [24]
3 years ago
5

The bullet starts at rest in the gun. An 8.6 g bullet leaves the muzzle of a rifle with a speed of 430.1 m/s. What constant forc

e is exerted on the bullet while it is traveling down the 0.5 m length of the barrel of the rifle?
Physics
1 answer:
xenn [34]3 years ago
3 0

Answer:

The constant force exerted on the bullet is 1590.87 N.

Explanation:

It is given that,

Mass of the bullet, m = 8.6 g

Initial speed of the bullet, u = 0          

Final speed of the bullet, v = 430.1 m/s

We need to find the force exerted on the bullet while it is traveling down the 0.5 m length of the barrel of the rifle. Let a is the acceleration of the bullet. So,

v^2-u^2=2ad

v^2=2ad

a=\dfrac{v^2}{2d}

a=\dfrac{(430.1)^2}{2\times 0.5}

a=184986.01\ m/s^2

Let F is the force exerted. It is given by :

F=ma

F=8.6\times 10^{-3}\times 184986.01

F = 1590.87 N

So, the constant force exerted on the bullet is 1590.87 N. Hence, this is the required solution.                                                  

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devlian [24]

Answer:

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To send out a radio signal far and wide.. it is called: broadcast

Explanation:

5 0
3 years ago
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What is the kinetic energy of an object moving 40m/s with a mass of 20kg?
Svet_ta [14]
KE = (1/2) (mass) (speed)²

KE = (1/2) (20 kg) (40 m/s)²

KE = (1/2) (20 kg) (1,600 m²/s²)

KE = (10 kg) (1,600 m²/s²)

KE = 16,000 Joules
7 0
3 years ago
Two similar fans are operating in a room. Fan 1 makes a squeaking noise while running. Fan 2 is silent.
REY [17]

Answer:

a

Explanation:

because it has more energy

8 0
3 years ago
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A hot air balloon lifts 50 meters vertically into the air and then comes back down. What are the displacement and distance of th
Marysya12 [62]

Given that a hot air balloon lifts 50 meters vertically into the air and then comes back down.

The displacement is the distance covered in a specific direction.

When the balloon is going up, the displacement is positive. and when the balloon is coming down, the displacement is negative.

The total displacement = 50 - 50 = 0

The distance is a measurement of length between to different points or position.

For distance, there is no need to consider direction. There is no consideration for positive or negative signs

While the distance = 50 + 50 = 100 meters

Therefore, the correct answer is C

That is, The displacement is zero and the distance is 100 meters

Learn more on ; brainly.com/question/24662122

4 0
2 years ago
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A charge of -3.02 μC is fixed in place. From a horizontal distance of 0.0377 m, a particle of mass 9.43 x 10^-3 kg and charge -9
Andreyy89

Answer:

d = 0.0306 m

Explanation:

Here we know that for the given system of charge we have no loss of energy as there is no friction force on it

So we will have

U + K = constant

\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2

now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.

So we have

\frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{0.0377} + \frac{1}{2}(9.43 \times 10^{-3})(80.4)^2 = \frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{r} + 0

7.05 + 30.5 = \frac{0.266}{r}

r = 7.08 \times 10^{-3} m

so distance moved by the particle is given as

d = r_1 - r_2

d = 0.0377 - 0.00708

d = 0.0306 m

6 0
3 years ago
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