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disa [49]
3 years ago
15

Based on the vibrational difference you observed, state a hypothesis to explain why diatomic molecules in the air, such as oxyge

n and nitrogen, are not greenhouse gases while those with 3 or more atoms, such as methane, are?
Chemistry
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer:

See explanation

Explanation:

The ability of a gas to function as a green house gas depends on its ability to absorb infra red rays. In turn, the absorption of infrared red rays depends on whether or not the molecule is IR active.

The triatomic molecules such as methane and water are IR active. Only IR active molecules can lead to green house effect.

Note that for a molecular vibrational mode to be IR active, the dipole moment of the molecule is changed as the vibration occurs .

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jasenka [17]

Ok, I will help you answer but it is very hard to read could you enlarge it first?

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5 0
3 years ago
Making solutions is an extremely important component to real-life chemistry. If you make 3.00 L of a solution using 90.0 g of so
kumpel [21]

Answer:

Final concentration of NaOH = 0.75 M

Explanation:

For NaOH :-

Given mass = 90.0 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{90.0\ g}{39.997\ g/mol}

Moles\ of\ NaOH= 2.2502\ mol

Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.

The expression for the molarity, according to its definition is shown below as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Where, Volume must be in Liter.

It is denoted by M.

Given, Volume = 3.00 L

So,

Molarity=\frac{2.2502\ mol}{3.00\ L}=0.75\ M

<u>Final concentration of NaOH = 0.75 M</u>

5 0
4 years ago
Which of the following measurements has FOUR significant figures?
garik1379 [7]

Answer:

A) 0.1005 m

sorry if it's wrong

7 0
3 years ago
I need help with number 3. is the answer 1,2,3,or4
lubasha [3.4K]

Answer:

1 and 4

Explanation:

in both pictures the temperature is cooling down

8 0
4 years ago
What mass of ammonia can be produced if 13.4 grams of nitrogen gas reacted ?
aivan3 [116]

Answer:

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

Explanation:

Step 1: Data given

Mass of nitrogen gas (N2) = 13.4 grams

Molar mass of N2 = 28 g/mol

Molar mass of NH3 = 17.03 g/mol

Step 2: The balanced equation

N2 + 3H2 → 2NH3

Step 3: Calculate moles of N2

Moles N2 = Mass N2 / molar mass N2

Moles N2 = 13.4 grams / 28.00 g/mol

Moles N2 = 0.479 moles

Step 4: Calculate moles of NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 0.479 moles N2 we'll produce 2*0.479 = 0.958 moles

Step 5: Calculate mass of NH3

Mass of NH3 = moles NH3 * molar mass NH3

Mass NH3 = 0.958 moles * 17.03 g/mol

Mass NH3 = 16.3 grams

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

3 0
3 years ago
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