The boiling point depends on the strength of the intermolecular forces holding the molecules together. Greater the force, higher is the boiling point.
The intermolecular force increases in the order shown below:
ion-ion > H-bonding > dipole-dipole > London dispersion
CH3CN is a polar molecule with strong dipole-dipole forces
CH3CH2CH3 is non-polar held by london dispersion
Ar exist as a gas. It will have a lowest boiling point
Thus the order of decreasing b.pt is:
CH3CN > CH3CH2CH3 > Ar
I believe it is B. Green pods are recessive.
There will be 1.11 grams of the sample of radon-222 left. This answer can be obtained using the formula of half life to get the rate constant which will be used in another equation later on.
Half-life (t) = ln2/k = 3.8 days
k = 0.182407/day
Using the general equation of a first order reaction:
Ca/Cao = 1/e^(kt)
Ca/Cao = 0.01506 --> fraction of radon-222 left
This means that 1.51% of the original amount remains, so 1.51% of 73.9 is 1.11 grams.
O He was always very gauche and urbane in polite society
The balanced equation for the above reaction is as follows;
3NaOH + H₃PO₄ ---> Na₃PO₄ + 3H₂O
stoichiometry of NaOH to H₃PO₄ is 3:1
the number of NaOH moles in the solution - molarity x volume
number of NaOH moles - 0.3 mol/L x 0.030 L = 0.009 mol
for complete neutralisation
3 mol of NaOH requires 1 mol of H₃PO₄
therefore 0.009 mol of NaOH requires - 1/3 x 0.009 = 0.003 mol of H₃PO₄
therefore 0.003 mol of H₃PO₄ are needed to reach the equivalence point