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densk [106]
3 years ago
7

Making solutions is an extremely important component to real-life chemistry. If you make 3.00 L of a solution using 90.0 g of so

dium hydroxide, what is the final concentration?
Chemistry
1 answer:
kumpel [21]3 years ago
5 0

Answer:

Final concentration of NaOH = 0.75 M

Explanation:

For NaOH :-

Given mass = 90.0 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{90.0\ g}{39.997\ g/mol}

Moles\ of\ NaOH= 2.2502\ mol

Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.

The expression for the molarity, according to its definition is shown below as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Where, Volume must be in Liter.

It is denoted by M.

Given, Volume = 3.00 L

So,

Molarity=\frac{2.2502\ mol}{3.00\ L}=0.75\ M

<u>Final concentration of NaOH = 0.75 M</u>

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Complete the reaction, which is part of the electron transport chain. The abbreviation Q represents coenzyme Q. Use the appropri
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Answer:

x = 2+

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7 0
3 years ago
A. At STP, what is the volume of 708 mol of nitrogen gas? 708 mol = 708 mol X L B. A sample of hydrogen gas occupies 14.1 L at S
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B. 0.629 mol

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5 0
2 years ago
In a similar analysis, a student determined that the percent of water in the hydrate was 25.3%. the instructor informed the stud
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Answer is: f<span>ormula for the hydrated compound is CuSO</span>₄·3H₂O.
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ω(CuSO₄) = 74,7% = 0,747.
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M(H₂O) = 54 g/mol.
N(H₂O) = 54 g/mol ÷ 18 g/mol.
N(H₂O) = 3.
5 0
3 years ago
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