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Arisa [49]
2 years ago
14

What is the answer to -3(x+4)+15=6-4x

Mathematics
1 answer:
vredina [299]2 years ago
5 0

The answer is -12

Remember pemdas

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Kensington City Cafe recently introduced a new flavor of coffee. They served 28 grande cups
Dmitrij [34]

Answer:

jumbo 23 oz, grande 16 oz

Step-by-step explanation:

Use g for grande and j for jumbo

The first equation: 28g + 33j = 1207

The second equation: 28g + 53j = 1667

Subtract the first from the second

   28g + 53j = 1667

-   28g + 33j = 1207

Equal 20j = 460

j = 23

Put 23 in for j in either equation and solve for g:

28g + 33(23) = 1207

28g + 759 = 1207

28g = 448

g = 16

5 0
2 years ago
-5x +3y +6z=4<br> -3x + y + 5z=-5<br> -4x + 2y + z= 13
lozanna [386]

See the attached image for solution:

6 0
3 years ago
Read 2 more answers
In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion
lys-0071 [83]

\displaystyle&#10;(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k

<em>-------------------------------------------------------------</em>


\displaystyle&#10;(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\&#10;n=5\\&#10;k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10

<u>It's 10.</u>

----------------------------------------------------

\displaystyle&#10;(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\&#10;n=5\\&#10;k=4\\\\&#10;\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90

<u>It's 90</u>

6 0
3 years ago
Find the midpoint of the segment with the following endpoints.<br> (10, 7) (2, 1)
Alex_Xolod [135]

Answer:

(6,4)

Step-by-step explanation:

Midpoint=((x1+x2)/2 ,(y1+y2)/2)

((10+2)/2 ,(7+1)/2)

(6,4)

x1=10

x2=2

y1=2

y2=1

7 0
2 years ago
The mean number of travel days per year for salespeople employed by three hardware distributors needs to be estimated with a 0.9
bearhunter [10]

Answer:

133

Step-by-step explanation:

7 0
3 years ago
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