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3 years ago

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Physics

2 answers:

yuradex [85]3 years ago

7 0

I think it B I’m not sure

MatroZZZ [7]3 years ago

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Bbbbbbbbbbbbbbbbbbbbbbbbbb

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A force of 1.00 x 10^2 pounds acts at an angle of 60.0° to the x-axis. (The force is accurate to 3 significant figures.) What ar

tamaranim1 [39]

Answer:

Fx= 50.0 Pounds : Components of the force along the x-axis

Fy= 86.6 Pounds : Component of the force along the y-axis

Explanation:

Conceptual Analysis

To find the components (Fx, Fy) of the total force (F), we apply the trigonometric concepts for a right triangle, where the perpendicular sides of the triangle are the components (Fx, Fy) of the force (F), the hypotenuse (h) is the magnitude of the total force F and β is the angle that forms the horizontal component with the hypotenuse.

Formulas

cos β : x/h : x: side adjacent to the β angle h: hypotenuse (1)

sin β = y/h : y: side opposite to the β angle h: hypotenuse (2)

Known Data

Known data

F= 1.00 * 10² pounds = 100 pounds : magnitude of total force

β = 60.0° to the x-axis. : Angle that forms the force with the x-axis

Problem Development

We apply the formula 1 to calculate horizontal component (Fx)

cos β :Fx/F

Fx= F cosβ = 100*cos 60° = 50.0 Pounds

We apply the formula 2 to calculate vertical component (Fy)

sin β = Fy/F

Fy= F sinβ = 100*sin 60° = 86.6 Pounds

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4 years ago

In a tug of war, two teams exerts a force of 30 N each. What is the net force acting on the rope?

Arte-miy333 [17]

The force exerted by each team is 30 N. The forces are in the direction opposite to each other.

Force exerted by team 1, $F_{1}=30 N$

Force exerted by team 2, $F_{2}=-30 N$

Net force, $F=F_{1} +F_{2}$

$=30+(-30)=0$

Therefore, net force on the rope is 0 N.

4 0

3 years ago

In a little league baseball game, the 145 g ball enters the strike zone with a speed of 14.0m/s . the batter hits the ball, and

Novosadov [1.4K]

Answer:

5365 N

Explanation:

v = Final velocity = 23 m/s

u = Initial velocity = -14 m/s (opposite direction)

m = Mass of ball = 145 g

t = Time taken = 1 ms

Impulse is given by

$J=m(v-u)$

Impulse is also given by

$J=Ft$

$Ft=m(v-u)\\\Rightarrow F=\dfrac{m(v-u)}{t}\\\Rightarrow F=\dfrac{0.145\times (23-(-14))}{1\times 10^{-3}}\\\Rightarrow F=5365\ N$

The magnitude of the average force exerted by the bat on the ball is 5365 N

8 0

3 years ago

Object A has 25 J of kinetic energy. Object B has one-quarter the mass of object A.By what factor does the speed of each object

Natalka [10]

Answer:

The speed of object B is 2 times of speed of object A.

Explanation:

Given that,

Kinetic energy of object A = 25 J

Mass of object B $m_{B}=\dfrac{1}{4}m_{A}$

Work done = -20 J

We need to calculate the factor of the speed of the object

Suppose the final kinetic energy is same for both object.

$K.E_{f_{A}}=K.E_{f_{B}}$

$\dfrac{1}{2}m_{A}v_{A}^2=\dfrac{1}{2}m_{B}v_{B}^2$

Put the value into the formula

$\dfrac{1}{2}m_{A}\times v_{A}^2=\dfrac{1}{2}\times\dfrac{1}{4}m_{A}\times v_{B}^2$

$\dfrac{v_{A}}{v_{B}}=\dfrac{1}{2}$

$v_{A}=\dfrac{1}{2}v_{B}$

$v_{B}=2v_{A}$

Hence, The speed of object B is 2 times of speed of object A.

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3 years ago

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What happens after a new moon

mars1129 [50]

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