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erik [133]
3 years ago
11

Help quick pls!!!! And ty!!

Mathematics
1 answer:
Tanya [424]3 years ago
8 0

Answer:

1. parallelogram 2. polygon 3. trapezoid 4. square 5. trapezoid 6. parallelogram

Step-by-step explanation:

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Step-by-step explanation:

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How to solve<br> -22-x=5+6x+9
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  -22 - x = 5 + 6x + 9   Combine like terms (5 and 9)
  -22 - x = 14 + 6x        Subtract 6x from both sides
-22 - 7x = 14                Add 22 to both sides
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(5+6b^3)^2 expand and combine like terms
Drupady [299]

Answer:

( 5 + 6b^3)^2 = 36b^6 + 60b^3 + 25

Step-by-step explanation:

(a + b)^2 = a^2 + b^2 + 2ab

So,

        (5 + 6b^3)^2 = (5)^2 + (6b^3)^2 + 2 (5)(6b^3)

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7 0
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Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3 5 , KE = 8, LM KN = 3 5 Find: KM, LM, KN, Area of KLMN
prisoha [69]
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the 
KM² = KE² + ME²KM² = 8² + (3√5)²       = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N  Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the  formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM)          = 1/2 * 3√5 * (40 + 24)         = 1/2 * 3√5 * 64         = 3 x 2.23 * 32         = 214.66 units²
7 0
3 years ago
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