Firstly, let's create a function of f(t) where t represents the time that has past, and f(t) represents the amount of rainwater. We know that when t=1, then f(t)=10, and t=2 then f(t)=15. So, let's take that and analyze it:
(1,10)
(2,15)
m = (15-10)/(2-1) = 5
y-intercept = 5
∴ f(t) = 5t+5
Now we just evaluate t for 10:
f(10) = (5*10)+5
f(10) = 55
1/4 is the shortest all you have to do is multiply 2/5 by 4, 3/10 by 2, and 1/4 by 5
Answer: 2900185 Joules
Step-by-step explanation:
Force used to tow the car is 1600N
Angle(α)= 25
Displacement = 2km
Recall that 1km= 1000m
Therefore 2km= 2000m
Workdone= FdCos α
W= 1600 * 2000 * cos 25
W=2900184.919
W= 2900185 Nm(when approximated to the nearest integer)
Since 1J = 1Nm
Work done = 2900185 J
Answer:
The top option is false.
Step-by-step explanation:
Both segments have a <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] of ⅔. It just that their ratios have unique qualities:
Greatest Common Factor: 2
___ ___
<em>BC</em><em> </em>is at a 4⁄6 slope, and <em>AB</em><em> </em>is at a ⅔ slope. Although their quantities are unique, they have the exact same value.
I am joyous to assist you anytime.
Im pretty sure its 18 unless im reading it wrong
