Answer:
A sample size of 1031 is required.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is of:
37% of freshmen do not visit their counselors regularly.
This means that 
98% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
You would like to be 98% confident that your estimate is within 3.5% of the true population proportion. How large of a sample size is required?
A sample size of n is required.
n is found when M = 0.035. So
Rounding up:
A sample size of 1031 is required.
Answer:
please mark brainliest
it is true
Step-by-step explanation:
if you multiplie 80 by 0.50 you will get 40,
Problem 1:
1) 3/5x-1 x 3/4=9/10
3x/5-1 x 3/4=9/10
2) 3x/5-1 x 3/4=9/10
3x/5-3/4=9/10
3) 3x/5-3/4=9/10
+3/4 +3/4
4) 3x/5=33/20
5) 5 x 3x/5= 5 x (33/20)
6) 3x=33/4
7) 3x=33/4
/3 /3
8) x=11/4
Problem 2:
1) 6/7+2/5x=-4/5
6/7+2x/5=-4/5
2) 6/7+2x/5=-4/5
-6/7 -6/7
3) 2x/5= --58/35
4) 5 x 2x/5= 5 x (--58/35)
5) 2x= --58/7
6) 2x= --58/7
/2 /2
x= --29/7
Answer:
Miguel cabrera
Step-by-step explanation:
Given that :
Miguel cabrera's batting average = 0.33
Mike trout's batting average = 0.326
The average for both players was obtained during the same season:
Hence. Comparing their respective averages,
0.33 = 0.330
0.330 > 0.326
Hence, Miguel Cabrera's batting average is higher than that of Mike trout
