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andrew11 [14]
2 years ago
10

Hurry please need fast

Chemistry
1 answer:
Nina [5.8K]2 years ago
7 0
I think it might be 2 but I could be mistaken sorry if I am
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3. Methane (CH4) behaves as an ideal gas under standard temperature and pressure conditions. What volume is occupied by 1 kg of
AlekseyPX

Answer:

1711.11L

Explanation:

Given parameters:

Mass of methane = 1kg = 1000

Temperature of gas = 35°C

Pressure of the gas = 0.9atm

Converting to the temperature to kelvin, we have:

               35+ 273 = 308k

Solution

From the given parameters, we can solve this problem using the ideal gas equation which is combination of the gas laws. It is expressed below:

                                         PV = nRT              .......................(i)

Where P is the pressure of the gas

             V is the volume of the gas

             n is the number of moles

             R is the gas constant

             T is the temperature

Now, from the above parameters, we have two unknowns which are n and V.

To find the number of moles n, we use the expression below:

         number of moles = \frac{mass}{molar mass}

        molar mass of methane = 12 + (4x1) = 16g/mol

       Number of moels of methane =  \frac{1000}{16} = 62.5mole

Now that we know the number of moles, we can make the unknown Volume the subject of the formula:

                     V = \frac{nRT}{P}

                     V =  \frac{62.5 x 0.082 x 308}{0.9} = 1711.11L

7 0
3 years ago
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