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Verdich [7]
3 years ago
7

Calculate the empirical formula of a compound that is 42.9% Carbon and 57.1% Oxygen.

Chemistry
1 answer:
Marrrta [24]3 years ago
4 0

Answer:

CO.

Explanation:

Assuming the given percentages are by mass, we can solve this problem via imagining we have <em>100 g of the compound</em>, if that were the case we would have:

  • 42.9 g of C
  • 57.1 g of O

Now we <u>convert those masses into moles</u>, using the<em> elements' respective molar masses</em>:

  • 42.9 g of C ÷ 12 g/mol =  3.57 mol C
  • 57.1 g of O ÷ 16 g/mol =  3.58 mol O

As the number of C moles and O moles is roughly the same, the empirical formula for the compound is <em>CO</em>.

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Answer:

1). 19.9

2). 0

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