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Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K
Explanation :
We have to calculate the entropy change of reaction .
where,
= entropy of reaction = ?
n = number of moles
= standard entropy of
= standard entropy of
= standard entropy of
Now put all the given values in this expression, we get:
Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K