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3 years ago

PLEASE HELP WILL MARK BRAINLIEST *

Physics

1 answer:

Travka [436]3 years ago

8 0

THE ANSWER IS FALSE AND GOOD LUCK ON YOUR TEST

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Toddlers are extremely active, naturally curious, and very top heavy making them prone to falls. The disproportionately large he

Serhud [2]

Answer:

Explanation:

6 0

4 years ago

If a ball is thrown vertically upward with a velocity of 128 ft/s, then its height after t seconds is s = 128t − 16t2.

Fed [463]

Answer:

a) 256 ft

b) 32 ft/s

c) -32 ft/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 32 ft/s²

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-128^2}{2\times -32}\\\Rightarrow s=256\ ft$

Maximum height = 256 ft

When s = 240 ft

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times -32\times 240+128^2}\\\Rightarrow v=32\ ft/s$

Speed of the ball at 240 ft is 32 ft/s while going up

Now this will be the velocity of the ball when it reaches 240 ft, which will be considered as the initial velocity

$v=u+at\\\Rightarrow 0=32-32t\\\Rightarrow t=\frac{-32}{-32}=1\ s$

Now, initial velocity will be considered as zero

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 32\times 16+0^2}\\\Rightarrow v=32\ ft/s$

Speed of the ball at 240 ft is -32 ft/s while going down

3 0

3 years ago

Determine the resistance of a 250-w lightbulb connected to its proper source voltage of 110 v.

ollegr [7]

1.P=UI
2.U=IR
so P=U^2/R
R=U^2/P=110*110/250=48.4ohm

5 0

3 years ago

Hydrogen bonds are weaker than the bond that holds hydrogen to oxygen in a

gulaghasi [49]

Answer:

Your answer is false

Explanation:

5 0

3 years ago

A square coil, enclosing an area with sides 2.0 cm long, is wrapped with 2 500 turns of wire. A uniform magnetic field perpendic

Delvig [45]

Answer:

The induced voltage in the coil is 0.25 V.

Explanation:

It is given that,

Area of a square coil is 2 cm or 0.02 m

Number of turns in the wire is 2500

A uniform magnetic field perpendicular to its plane is turned on and increases to 0.25 T during an interval of 1.0 s.

We need to find the induced voltage in the coil. According to Faraday's law, the induced emf in the coil is given by the rate of change on magnetic flux. So,

$\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(NBA)}{dt}\\\\\epsilon=NA\dfrac{-dB}{dt}\\\\\epsilon=-2500\times (0.02)^2\times \dfrac{0.25}{1}\\\\\epsilon=-0.25\ V$

So, the induced voltage in the coil is 0.25 V.

3 0

3 years ago