Taking into account the Charles's law, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.
<h3>Charles's Law</h3>
Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, at a constant pressure.
Volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.
Mathematically, Charles's law is a law that says that the quotient that exists between the volume and the temperature will always have the same value:
V÷ T= k
Considering an initial state 1 and a final state 2, it is satisfied:
V1÷ T1= V2÷ T2
<h3>Volume at 65°C</h3>
In this case, you know:
- V1= 22.4 L
- T1= 0 C= 273 K
- V2= ?
- T2= 65 C= 338 K
Replacing in Charles's law:
22.4 L÷ 273 K= V2÷ 338 K
Solving:
(22.4 L÷ 273 K) ×338 K= V2
<u><em>V2= 27.73 L</em></u>
Finally, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.
Learn more about Charles's law:
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