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The current in the ideal diode with forward biased voltage drop of 65V is 132.6 mA.
To find the answer, we have to know more about the ideal diode.
<h3>What is an ideal diode?</h3>- A type of electronic component known as an ideal diode has two terminals, only permits the flow of current in one direction, and has less zero resistance in one direction and infinite resistance in another.
- A semiconductor diode is the kind of diode that is used the most commonly.
- It is a PN junction-containing crystalline semiconductor component that is wired to two electrical terminals.
- Here we have given with the values,
- We have the expression for current in mA of the ideal diode with forward biased voltage drop as,
Thus, we can conclude that, the current in mA of the ideal diode with forward biased voltage drop of 65 V is 132.6.
Learn more about the ideal diode here:
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Answer:
A. The upward pressure gradient force is balanced by gravity.
Explanation:
A. is correct because the pressure difference is actually generated by gravity. As in the following formula for the pressure at different points:
where are the pressure at 2 points, ρ is the density of the fluid, g is the gravitational constant, and h is the height difference.
B is incorrect because friction in air is too small to make an effect.
C is incorrect because the Coriolis force is horizontal, not vertical.
D is incorrect because a difference of 500 hPa = 50000 Pa, this is half of the atmospheric pressure.
E is incorrect because temperature cannot generate force.