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Lina20 [59]
3 years ago
14

When 2.00 kJ of energy is transferred as heat to nitrogen in a cylinder fitted with a piston with an external pressure of 2.00 a

tm, the nitrogen gas expands from 2.00 to 5.00 L. What is the change in internal energy of this system? (1 L·atm = 0.1013 kJ)
Physics
1 answer:
julia-pushkina [17]3 years ago
3 0

Answer:

ΔU= 1.3922 KJ

Explanation:

Given that

Q= 2 KJ  

Note- 1 .Heat added to the system taken as positive and heat leaving from the system is taken negative.

2. Work done on the system taken as negative and work done by the system taken as positive.

P =2 atm

V₁= 2 L

V₂=5 L

Work done by the gas W

W= P ( V₂- V₁)

W= 2 ( 5 - 2)

W= 6 atm.L

1 L·atm = 0.1013 kJ

W= 0.6078 KJ

From first law of thermodynamics

Q= W + ΔU

ΔU=Change in internal energy

2 = 0.6078 +  ΔU

ΔU= 1.3922 KJ

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Answer in Explanation

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In this experiment we will observe the magnetic fields produced by a current carrying wire. A long wire is suspended vertically,
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Answer:

See explanation

Explanation:

Solution:-

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( See attachments )

- The equation for the magnetic field strength - B - (magnitude) produced by a long straight current-carrying wire is given by the Biot Savart Law:

                                  B = \frac{uo*I}{2\pi *r}

Where,

I : The current,

r : The shortest distance to the wire,

uo : The permeability of free space. = 4π * 10^-7  T. m/A

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 3)  r^ is a unit vector in the direction of r.

   

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