To have a weight of 2.21N., the ball's mass is (2.21/9.8) = .226kg.
<span>a) d = 1/2 (vt), = 1/2 (18 x .17), = 1.53m. </span>
<span>b) Acceleration of the ball = (v/t), = 18/.17, = 105.88m/sec^2. </span>
<span>f = (ma), = .226 x 105.88, = 23.92N. </span>
The first thing we are going to do for this case is to model the igloo as a hemisphere.
The volume of the hemisphere is:
V = ((4/3) * (pi) * (r ^ 3)) / 2
Where,
r: sphere radio
We have then that the internal diameter is:
di = 12-1.5
di = 10.5 feet
So the radio is:
r = di / 2
r = 10.5 / 2
r = 5.25 feet
Substituting values:
V = ((4/3) * (pi) * ((5.25) ^ 3)) / 2
V = 303.1 feet ^ 3
Answer:
the amount of space of the living area inside the igloo is:
V = 303.1 feet ^ 3
Answer:
Step-by-step explanation:
1. Express each quadratic function f in the form f (x) -yo = p (x - xo) x ϵ R, where xo, i, p ϵ R are appropriately chosen. Indicate the coordinates
of the vertex of the parabola, the minimum or maximum of the function f, especially R. Draw the graph of f.
a) f (x) = 2x2 + 3x -5, ϵ R,
b) f (x) = -3x2 + 7x +9, ϵ R,
c) f (x) = - x +1, ϵ R,
HELP YOU GIVE YOU CORONA PLIS
Answer:
P = 100
Area = 625
Step-by-step explanation:
Area = s^2
sqrt(area) = sqrt(s^2)
area = 25*25
sqrt(25*25) = sqrt(s^2)
s = 25
P = 4*s
P = 4 * 25
P = 100
Area = s^2
s = 25
Area = 25^2
Area = 625
