What is the daughter nuclide when 0-15 experiences positron emission?
1 answer:
The daughter isotope (a decay product)of O-15 = N-15(Nitrogen 15)
<h3>Further explanation </h3>Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,
- alpha α particles ₂He⁴
- beta β ₋₁e⁰ particles
- gamma particles γ
- positron particles ₁e⁰
O-15 emits positron particles ₁e⁰, so the atomic number decreases by 1, the mass number is the same
Reaction
The mass number of the daughter isotope = 15, atomic number = 7
If we look at the periodic system, the element with atomic number 7 is Nitrogen (N)
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Answer:
3.5 mol·L⁻¹
Explanation:
1. Set up an ICE table.
2. Solve for x
The equilibrium concentration of NO is 1.0 mol·L⁻¹, so
1.0 = 2.0 - 2x
2x + 1.0 = 2.0
2x = 1.0
x = 0.5
3. Calculate the equilibrium concentration of I₂
[I₂] = 4.0 - x = 4.0 - 0.5 = 3.5 mol·L⁻¹