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3 years ago

What is the daughter nuclide when 0-15 experiences positron emission?

Chemistry

1 answer:

Helen [10]3 years ago

5 0

The daughter isotope (a decay product)of O-15 = N-15(Nitrogen 15)

<h3>Further explanation </h3>

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,

alpha α particles ₂He⁴
beta β ₋₁e⁰ particles
gamma particles γ
positron particles ₁e⁰

O-15 emits positron particles ₁e⁰, so the atomic number decreases by 1, the mass number is the same

Reaction

$\tt _8^{15}O\Rightarrow _7^{15}N+_1^0e$

The mass number of the daughter isotope = 15, atomic number = 7

If we look at the periodic system, the element with atomic number 7 is Nitrogen (N)

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yawa3891 [41]

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3 years ago

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Which of these is not a mixture

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3 years ago

How much work (in J) is involved in a chemical reaction if the volume decreases from 5.00 to 1.48 L against a constant pressure

Dahasolnce [82]

Given:
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p = 0.818 atm = 0.819*101325 Pa = 82985.2 Pa

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3 years ago

Which of the following represent chemical processes? Which represent physical processes?

Viktor [21]

Answer:

A). Calcium chloride dihydrate (CaCl2 * 2H2O) slowly heated in a crucible to become calcium chloride (anhydrous).

Dehyration is a physical process

B). A hydrocarbon such as propane (C3H8) undergoes combustion to power a grill

Combustion is a chemical process.

C). A rock climber’s rope becomes frayed and turns the color of the rocks

This is physical process

D). A dog urinates on an air conditioner coil and the coil becomes corroded

Corrsion is a chemical process.

Explanation:

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3 years ago

student has calibrated his/her calorimeter and finds the heat capacity to be 14.2 J/°C. S/he then determines the molar heat capa

nika2105 [10]

Answer:

24.03 J/mol.ºC

Explanation:

For a calorimeter, the heat lost must be equal to the heat gained from water plus the heat gained from calorimeter, which has the same initial temperature as the water.

-Qal = Qw + Qc (minus signal represents that the heat is lost)

-mal*Cal*ΔTal = mw*Cw*ΔTw + Cc*ΔTc

Where m is the mass, C is the specific heat, ΔT is the temperature variation, al is from aluminum. w from water and c from the calorimeter. Cw = 4.186 J/gºC

-25.5*Cal*(22.7 - 100) = 99.0*4.186*(22.7 - 18.6) + 14.2*(22.7 - 18.6)

1971.15Cal = 1699.10 + 58.22

1971.15Cal = 1757.32

Cal = 0.89 J/g.ºC

The molar mass of Al is 27 g/mol

Cal = 0.89 J/g.ºC * 27 g/mol

Cal = 24.03 J/mol.ºC

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3 years ago