What is the daughter nuclide when 0-15 experiences positron emission?
1 answer:
The daughter isotope (a decay product)of O-15 = N-15(Nitrogen 15)
<h3>Further explanation </h3>Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,
- alpha α particles ₂He⁴
- beta β ₋₁e⁰ particles
- gamma particles γ
- positron particles ₁e⁰
O-15 emits positron particles ₁e⁰, so the atomic number decreases by 1, the mass number is the same
Reaction
The mass number of the daughter isotope = 15, atomic number = 7
If we look at the periodic system, the element with atomic number 7 is Nitrogen (N)
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Answer:
Explanation:
Density is m/V. Also, 1 liter = 1000 . So, we get 0.890/(5*1000) =
g/cm^3. You can convert this to kg/m^3 as well by multiplying it by 10. Depends which one you want.