What is the daughter nuclide when 0-15 experiences positron emission?
1 answer:
The daughter isotope (a decay product)of O-15 = N-15(Nitrogen 15)
<h3>Further explanation </h3>Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,
- alpha α particles ₂He⁴
- beta β ₋₁e⁰ particles
- gamma particles γ
- positron particles ₁e⁰
O-15 emits positron particles ₁e⁰, so the atomic number decreases by 1, the mass number is the same
Reaction
The mass number of the daughter isotope = 15, atomic number = 7
If we look at the periodic system, the element with atomic number 7 is Nitrogen (N)
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Answer:
1. was the
value calculated by the student.
2. was the
of ethylamine value calculated by the student.
Explanation:
1.
The value of Aspirin solution = 2.62
Moles of s asprin =
Volume of the solution = 0.600 L
The initial concentration of Aspirin = c =
initially
c 0 0
At equilibrium
(c-x) x x
The expression of dissociation constant :
:
was the
value calculated by the student.
2.
The value of ethylamine = 11.87
The initial concentration of ethylamine = c = 0.100 M
initially
c 0 0
At equilibrium
(c-x) x x
The expression of dissociation constant :
:
was the
of ethylamine value calculated by the student.