Question

What is the daughter nuclide when 0-15 experiences positron emission?

Answer 1

The daughter isotope (a decay product)of O-15 = N-15(Nitrogen 15)

Further explanation

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

• alpha α particles ₂He⁴
• beta β ₋₁e⁰ particles
• gamma particles γ
• positron particles ₁e⁰

O-15 emits positron particles ₁e⁰, so the atomic number decreases by 1, the mass number is the same

Reaction

 $\tt _8^{15}O\Rightarrow _7^{15}N+_1^0e$

The mass number of the daughter isotope = 15, atomic number = 7

If we look at the periodic system, the element with atomic number 7 is Nitrogen (N)