Answer:
The area under a velocity-time graph is the displacement. Velocity can be negative if an object is moving backwards. The displacement can also be negative. An area beneath the x-axis has a negative value.
Answer: this statement makes sense.
Explanation:
Supernova explosion is a bright powerful explosion of the start, it takes place at the end of the cycle of a star. This explosion is caused by having too much matter in it's core, As the star runs out of nuclear fuel, some of its mass flows into its core. Eventually, the core is so heavy that it cannot withstand its own gravitational force. The core collapses, which results in a massive explosion of a supernova. During this explosion Elements heavier than iron are formed. An uranium atom is heavier than an iron atom, so uranium falls into this category of elements that comes from supernova explosion.
Answer:
Resultant force = (232.93î + 246.10j) N
x-component of the resultant force = (+232.93î) N
y-component of the resultant force = (+246.1j) N
Explanation:
The net external force on the statue is equal to the resultant force on the statue.
And the resuphant force is a vector sum of all the other forces acting on the statue.
Force 1 = (45î) N
Force 2 = (105j) N
Force 3 = (235cos 36.9°)î + (235 sin 36.9°)j = (187.93î + 141.10j) N
Resultant force = (Force 1) + (Force 2) + (Force 3)
Resultant force = 45î + 105j + (187.93î + 141.10j) = (232.93î + 246.10j) N
Hope this helps!!!
First of all,
The electric field at the surface of the sphere is given by
E = kQ/r²
The field strength at which breakdown occurs in the air is <span>3.0 MV/m
</span>
So, E = 3.0 MV/m
<span>The sphere potential is defined as
V = kQ/r</span>
<span>If we divide E/V we get
E = V/r </span>
<span>r = V/E = 20000V / 3.10^6 V/m = 6.66 </span>10^-3 m = 6.66 mm
2. Charge
<span>V = kQ/r .............>>
</span>
Q = Vr/k = 20000V *( 6.66 10^-3 m)/ (9.10^9 N m2/C2) = 1.481 10^-8 C
Answer:
Constructive interference
Explanation:
- This is an example of a standing wave produced when two ends of a string are oscillated in the same plane. The displacement of of point on two ends oscillates vertically.
- We are given that two pulses move along the string each coming towards each other and meet at a common point ( P ).
- Each pulse have their own magnitude or displacement in the vertical plane. If the pulses are to meet at a common point at the same instant, then they interfere with each other constructively.
- Where constructive interference of two pulses is the addition of magnitudes of induvidual pulses and form a single puls of the constructed magnitude.
magnitude ( New pulse ) = magnitude (Pulse 1) + magnitude (Pulse 2)