Question

In the diagram, q1 = -3.33*10^-9 C and

Answer 1

Answer:

The distance will be "0.319 m".

Explanation:

The diagram of the given question is not attached with the problem. Below is the attached figure.

The given values are:

$q1 = -3.33\times 10^{-9} \C$

$q2 = -5.22\times 10^{-9} \ C$

As we know,

The electric field will be equivalent as well as opposite throughout the direction, then

⇒ $\frac{R.q1}{(0.255)^2} =\frac{R.q2}{r^2}$

⇒ $r^2=\frac{q2}{q1}\times (0.255)^2$

By putting the values, we get

⇒      $=\frac{-5.22\times 10^{-9}}{-3.33\times 10^{-9}}\times (0.255)^2$

⇒      $=1.568\times 0.065$

⇒  $r^2=0.10193$

⇒  $r=\sqrt{0.10193}$

⇒     $0.319 \ m$