3 years ago

According to this graph, the acceleration

Physics

1 answer:

skelet666 [1.2K]3 years ago

7 0

Answer:

1 m/s^2

Explanation:

a=(v-u)/t

where,

a=acceleration

v=final velocity

u=initial velocity

(4.5-0)/4.5

1 m/s^2

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The fixed hydraulic cylinder C imparts a constant upward velocity v = 2.2 m/s to the collar B, which slips freely on rod OA. Det

Olenka [21]

Answer:

so angular velocity is 7.13128 sec−1

Explanation:

velocity v = 2.2 m/s

displacement s = 220 mm = 0.220 m

distance d = 510 mm = 0.510 m

to find out

angular velocity

solution

we know that

angular velocity will be velocity ( v) / (displacement² + distance²) .....1

now put all these value in equation 1 and we get angular velocity i.e.

angular velocity = velocity ( v) / (displacement² + distance²)

angular velocity = 2.2 / (0.22² + 0.51²)

angular velocity = 2.2 / 0.3085

angular velocity = 7.13128

so angular velocity is 7.13128 sec−1

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3 years ago

The world's largest tires have a mass of 6000 kg

nikitadnepr [17]

Okay! Thank you for this knowledge

8 0

3 years ago

I have no idea of how to approach this problem

nataly862011 [7]

Answer:

p=1

Explanation:

Well me know that v=m/s

and that a=m/s^2

$(m/s)^{2} = (m/s^2)(x^p)\\\\(m^2/s^2)/(m/s^2)=x^p\\\\m^2s^2/ms^2=x^p\\\\(m^2/m)(s^2/s^2)=x^p\\\\m=x^p\\\\p=1$

Note: We don't take into account 2 because it's a scalar, it doesn't have units so it doesn't add anything to the equation.

4 0

3 years ago

The decomposition of water into hydrogen gas H2 and oxygen gas O2 can be modeled by the balanced chemical equation

Volgvan

2H2O->2H2+O2

This balanced chemical equation represents the decomposition of water into hydrogen gas and oxygen gas

3 0

3 years ago

Read 2 more answers

What is the gravity force between two stars with mass of 5,000,000 kg and 1,000,000 kg if the distance between them is 100 m

Luda [366]

Answer:

0.0334N

Explanation:

Given parameters:

M1 = 5 x 10⁶kg

M2 = 1 x 10⁶kg

Distance = 100m

Unknown:

Gravitational force = ?

Solution:

To solve this problem, we use the Newton's law of universal gravitation.

Fg = $\frac{G m1 m2}{r^{2} }$

G is the universal gravitation constant

m is the mass

r is the distance

Fg = $\frac{6.67 x 10^{-11} x 5 x 10^{6} x 1 x 10^{6} }{100^{2} }$ = 0.0334N

8 0

3 years ago