The answer to the question is the first opti.on.A
First, we apply the law of conservation of mass which states that the total mass in a system remains constant.
Therefore, there must be 5.00 g of sulfur and 4.99 g of oxygen in the product. Now, we determine the mass percentage using:
Mass % = (mass of sulfur x 100) / total mass of compound
Mass % = (5 * 100) / (5 + 4.99)
Mass % = 50.05%
The product contains 50.05% sulfur by mass.
Answer: 18g
Explanation:
1 mle of glucose combusts to give 6moles of CO2 and 6moles of H2O
C6H12O6 + 6O2-------- 6CO2 + 6H2O at STP.
Multiplying 6 by 3 moles we have 18 g of CO2
four covalent bonds in SiO2
