1. I get so much energy when I eat candy! What type of energy is this statement referring to?

A rock climber is going up a narrow space between two vertical rocks. The distance between the rocks allows the climber to brace

Roman55 [17]

Answer: b

Explanation:

7 0

4 years ago

5. A helicopter scoops a load of water out of a lake, to dump on a forest fire. The helicopter exerts 6480

Strike441 [17]

Answer:

h = 250 m

Explanation:

Given that,

The helicopter exerts 6480 N of force on the water while rising high enough to fly over a mountain.

The helicopter does $1.62\times 10^6\ J$ of work on the water lifting it.

We need to find how high does it lift the water. Work done is given by :

$W=Fh\\\\h=\dfrac{W}{F}\\\\h=\dfrac{1.62\times 10^6}{6480}\\\\h=250\ m$

So, it can lift the water to a height of 250 m.

6 0

3 years ago

. For transverse waves, compare the direction that the particles move to

Elza [17]

Answer:

The particles in transverse waves move perpendicular to the direction of how the wave moves.

Explanation:

5 0

3 years ago

A ball is tossed in the air and released. It moves up, reverses direction, falls back down again, and is caught at the same heig

PolarNik [594]

Answer:

The potential energy has a maximum when the ball is a time that is half of the time for total travel

Explanation:

Generally potential energy is a the varies directly with the height according to this formula

$PE =mgh$

and the ball attains a maximum height when the time is equal to half of the total time taken to travel

8 0

3 years ago

Read 2 more answers

A ball is thrown up into the air with 100 j of kinetic energy, which is transformed to gravitational potential energy at the top

jenyasd209 [6]

The kinetic energy when it returns to its original height is 100 J

Solution:

The ball is thrown up with a Kinetic Energy K. E. = 0.5×m×v² = 100 J

Therefore the final height is given by

Where:

u = final velocity = 0

v = initial velocity

s = final height

Therefore v² = 2·g·s = 19.62·s

P.E = Potential Energy = m·g·s

Since v² = 2·g·s

Substituting the value of v² in the kinetic energy formula, we obtain

K. E. = 0.5×m×2·g·s = m·g·s = P.E. = 100 J

When the ball returns to the original height, we have

v² = u² + 2·g·s

Since u = 0 = initial velocity in this case we have

v² = 2·g·s and the Kinetic energy = 0.5·m·v²

Since m and s are the same then 0.5·m·v² = 100 J.

As the height of the ball increases the kinetic energy of the ball is converted into gravitational potential energy. This means that the kinetic energy of the bullet is reduced. When the ball reaches its maximum height, it momentarily comes to rest and the ball's kinetic energy is zero. When the ball hits the ground, its potential energy is converted to kinetic energy.

Learn more about Kinetic energy here:-brainly.com/question/25959744

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6 0

1 year ago