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evablogger [386]
3 years ago
9

How is this model useful?

Chemistry
1 answer:
const2013 [10]3 years ago
6 0

Answer:

A) It shows how electrons are distributed in the Shells of an Iron atom.

Explanation: Took the test on Edge

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In your own words, describe the purpose of using a chemical equation.<br><br> PLEASEEEE HURRY
Soloha48 [4]

Answer:

Hey mate, here is your answer. Hope it helps you.

Explanation:

To show how substances in a chemical reaction interact and to keep track of all elements and the number of atoms in each element on each side of the equation.The purpose of writing a balanced chemical equation is to know: the reactants (starting material) and products (end results) that occur. the ratios in which they react so you can calculate how much reactants you need and how much products can be formed.

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What is the relationship between genes, chromosomes, and DNA? How are they organized inside of a cell?
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The rate constant for the second-order reaction 2NOBr(g) ¡ 2NO(g) 1 Br2(g) is 0.80/M ? s at 108C. (a) Starting with a concentrat
Valentin [98]

Answer:

(a)

0.0342M

(b)

t_{1/2}=17.36s\\t_{1/2}=23.15s

Explanation:

Hello,

(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:

\frac{1}{[NOBr]}=kt +\frac{1}{[NOBr]_0}\\\frac{1}{[NOBr]}=\frac{0.8}{M*s}*22s+\frac{1}{0.086M}=\frac{29.3}{M}\\

[NOBr]=\frac{1}{29.2/M}=0.0342M

(b) Now, for a second-order reaction, the half-life is computed as shown below:

t_{1/2}=\frac{1}{k[NOBr]_0}

Therefore, for the given initial concentrations one obtains:

t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.072M}=17.36s\\t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.054M}=23.15s

Best regards.

8 0
3 years ago
Read 2 more answers
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</span>
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3 years ago
One mole of a metallic oxide reacts with one mole of hydrogen to produce two moles of the pure metal
WARRIOR [948]

Answer:

Lithium oxide, Li₂O.  

Explanation:

Hello!  

In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:

M_2O+H_2\rightarrow 2M+H_2O  

Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:

5.00gM_2O*\frac{1molM_2O}{(2*X+16)gM_2O}*\frac{2molM}{1molM_2O}*\frac{XgM}{1molM}=2.32gM  

Thus, we perform the operations in order to obtain:

\frac{10X}{(2X+16)}=2.32  

So we solve for x as shown below:

10X=2.32(2X+16)\\\\10X=4.64X+37.12\\\\X=\frac{37.12}{10-4.64}\\\\X= 6.93g/mol  

Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.  

Best regards!

8 0
2 years ago
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