Plants have made a variety of reproductive adaptations to ensure the spreading and survival of their seed. A common example is the bright colors of many flowers. The purpose of this adaptation is to draw specific insects and birds that will visit the plant and distribute its pollen when they move on to the next plant.
Structural adaptations allow plants to live in specific environments, as is seen in the stark contrast between the roots of terrestrial plants, which are firmly rooted in the ground, and plants that float on the surface of bodies of water.
An example of a behavioral adaptation in plants is how certain desert plants have developed opportunistic behaviors that allow them to spring from dormancy to sudden reproductive activity during times of moisture and cool temperatures.
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Answer: combustion
Explanation:
Combustion reactions can be identified by looking at the reactants and the products.
Usually, the reactants will be a hydrocarbon and oxygen. And the products will be CO2 and H2O
Answer:
0.0970 M
Explanation:
Remember this equation:
mol/M x V
Convert it so that you can get M.
M=mol/V
Convert the 2.14 grams of H2SO4 into mols
=0.0218
Convert mL to L
225/1000
=0.225
Plug it in.
0.0218/0.225
=0.0970 M
Answer:
844.4cm³
Explanation:
Using Boyle's law equation;
P1V1 = P2V2
Where;
P1 = initial pressure (mmHg)
P2 = final pressure (mmHg)
V1 = initial volume (cm³)
V2 = final volume (cm³)
According to the information in this question,
V1 = 650cm³
P1 = 760mmHg
P2 = ?
V2 = 10% reduction of V1
10% of 650 = 10/100 × 650
65
V2 = 650 - 65 = 585cm³
Using P1V1 = P2V2
P2 = P1V1 ÷ V2
P2 = (760 × 650) ÷ 585
P2 = 494000 ÷ 585
P2 = 844.44
final pressure (P2) = 844.4cm³
