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3 years ago

What is the relationship between height of high tide and height of low tide for any location? ( Small answer please :) ! )

Physics

1 answer:

Lera25 [3.4K]3 years ago

7 0

Answer:

Tides are very long-period waves that move through the oceans in response to the forces exerted by the moon and sun. They originate in the oceans and progress toward the coastlines where they appear as the regular rise and fall of the sea surface. When the highest part or crest of the wave reaches a particular location, high tide occurs; low tide corresponds to the lowest part of the wave, or its trough. The difference in height between the high tide and the low tide is called the tidal range. Tidal range is the height difference between high tide and low tide.

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Two sacks contain the same number of identical apples and are separated by a distance r. The two

andrezito [222]

Answer:

The appropriate response will be " $F_2=\frac{3}{4}F$ ". A further explanation is given below.

Explanation:

According to the question,

⇒ $F_1=\frac{G(m_1 m_2)}{r^2}$ ....(equation 1)

and,

⇒ $F_2=\frac{G(m_1 m_2)}{r^2}$ ....(equation 2)

Now,

On dividing both the equations, we get

⇒ $\frac{F_1}{F_2}=\frac{\frac{G(2)(2)}{(1)^2}}{\frac{G(1)(3)}{(1)^2}}$

⇒ $\frac{F_1}{F_2}= \frac{4}{3}$

⇒ $F_2=\frac{3}{4}F$

4 0

3 years ago

The momentum of an object is determined to be 7.2 x 10-3 cm kg x m/s. Express this as provided or use any equivalent unit. How i

Leno4ka [110]

Complete Question:

The momentum of an object is determined to be 7.2 × 10-3 kg⋅m/s. Express this quantity as provided or use any equivalent unit. (Note: 1 kg = 1000 g).

Answer:

7.2 gm/s.

Explanation:

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

$Momentum = mass * velocity$

Given the following data;

Momentum = 7.2 * 10^-3 kgm/s

1 kg = 1000 g

Substituting the unit in kilograms with grams, we have;

Momentum = 7.2 * 10^-3 * 1000 gm/s

Momentum = 7.2 gm/s.

7 0

3 years ago

An ideal blackbody is an object that __________.a. absorbs most of the energy that strikes it. b. only absorbs energy at ultravi

STALIN [3.7K]

Answer:

c. absorbs all the energy that strikes it.

Explanation:

An ideal black body is an object that absorbs every light energy (irrespective of the wavelength and direction) that strikes it without reflecting any in return.

Such objects or bodies usually appear perfectly black and will only emit radiation when heated to a very high temperature.

6 0

3 years ago

A cannon with a muzzle speed of 1 000 m/s is used to start an avalanche on a mountain slope. The target is 2 000 m from the cann

Nataliya [291]

Answer:

∅ = 89.44°

Explanation:

In situations like this air resistance are usually been neglected thereby making g= 9.81 m/ $s^{2}$

Bring out the given parameters from the question:

Initial Velocity ( $V_{1}$ ) = 1000 m/s

Target distance (d) = 2000 m

Target height (h) = 800 m

Projection angle ∅ = ?

Horizontal distance = $V_{1x}$ tcos ∅ .......................... Equation 1

where $V_{1x}$ = velocity in the X - direction

t = Time taken

Vertical Distance = y = $V_{1y}$ t - $\frac{1}{2}$ g $t^{2}$ ................... Equation 2

Where $V_{1y}$ = Velocity in the Y- direction

t = Time taken

$V_{1y}$ = $V_{1}$ sin∅

Making time (t) subject of the formula in Equation 1

t = d/( $V_{1x}$ cos ∅)

t = $\frac{2000}{1000coso}$ = $\frac{2}{cos0}$ = $\frac{d}{cos o}$ ...................Equation 3

substituting equation 3 into equation 2

Vertical Distance = d = $V_{1y}$ $\frac{d}{cos o}$ - $\frac{1}{2}$ g $\frac{2}{cos0} ^{2}$

Vertical Distance = h = sin∅ $\frac{d}{cos o}$ - $\frac{1}{2}$ g $\frac{2}{cos0} ^{2}$

Vertical Distance = h = dtan∅ - $\frac{1}{2}$ g $\frac{2}{cos0} ^{2}$

Applying geometry

$\frac{1}{cos o}$ = $tan^{2} o$ + 1

Vertical Distance = h = d tan∅ - 2 g ( $tan^{2} o$ + 1)

substituting the given parameters

800 = 2000 tan ∅ - 2 (9.81)( $tan^{2} o$ + 1)

800 = 2000 tan ∅ - 19.6( $tan^{2} o$ + 1) Equation 4

Replacing tan ∅ = Q .....................Equation 5

In order to get a quadratic equation that can be easily solve.

800 = 2000 Q - 19.6 $Q^{2}$ + 19.6

Rearranging 19.6 $Q^{2}$ - 2000 Q + 780.4 = 0

$Q_{1}$ = 101.6291

$Q_{2}$ = 0.411

Inserting the value of Q Into Equation 5

tan ∅ = 101.63 or tan ∅ = 0.4114

Taking the Tan inverse of each value of Q

∅ = 89.44° ∅ = 22.37°

4 0

3 years ago

Newtons first law states that objects in motion stays in motion until an unbalanced force is acted upon it. what do you think th

EleoNora [17]

Hi Spycn2115

Newton's first law states that objects in motion stay in motion until an unbalanced force is acted upon it is a good fact. When I first personally heard of it in class I had no clue but when I researched it I learned that one good example of this would be those cradle balls and if u swing it, it will keep constantly hitting each other back and fourth over and over until someone grabs it and stops it, so that's what objects in motion stays in motion until an unbalanced force is acted upon it means, because the balls are in motion by moving left to right constantly and its staying in motion by not stopping and that unbalanced force is someone or something maybe hitting it or knocking it over could stop it, balanced means staying still and equal, unbalanced means unstill so moving, the cradle balls are KE and PE, (Kinect and potential energy) because kinetic means moving, so the balls are moving, and potential means stored up, so before u even swing u have the potential energy to swing it different ways before it becomes kinetic. That's one of my favorite examples of Newton's first law and I left you a pic below of cradle balls to help you get the idea.

8 0

3 years ago