Answer:
The rate of reaction is - 2.868 * 10^-4 M/S
Explanation:
In the following reaction: 2 NO + O2 → 2NO2
NO will be consumed, when adding O2.
This means it will disappear. This is confirmed by the concentration at 5 seconds and 650 seconds.
A = -Δ[A] / ΔT = [A2] - [A1] / T2 - T1
(0.225 - 0.04) / (650 - 5) = 0.185 / 645 = 2.868 * 10^-4 M/S
Since it will disappear, this number will be negative : - 2.868 * 10^-4 M/S
The rate of reaction is - 2.868 * 10^-4 M/S
Answer: see the last column in the final table of the explanation below.
Explanation:
1) Arrange the data to understand the question:
<span>Acid Molarity Moles of H⁺ released per liter
HCl 1 ____
H2SO4 1 ____
H3PO4 1 ____
H2SO4 0.5 ____
H3PO4 3 ____
HNO3 2 ____
</span><span>
2) All the given acids are strong acids, so you can consider they dissociate completely and release all the hydrogens present in the chemical formula.
3) The molarity formula is M = n/V, where n is the number of moles of solute and V is the volume of the solution in liters
From that, n = M×V
Go one by one with that formula.
</span>
Acid Molarity Moles of solute number of H in Moles <span><span>H⁺ </span> per liter the chemical formula per liter
HCl 1 1M×1L = 1 1 1×1 = 1
H₂SO4₄ 1 1M×1L = 1 2 2×1 = 2
H₃PO₄ 1 1M×1L = 1 3 3×1 = 3
H₂SO₄ 0.5 0.5M×1L = 0.5 2 2×0.5 = 1
H₃PO₄ 3 3M×1L = 3 3 3×3 = 9
HNO₃ 2 2M×1L = 2 2 2×2 = 4
</span>
Answer:
69.4kg
Explanation:
mole =volume/1000 * mole conc.
=1250/1000 * 0.75
mole =0.9
:• mole =mass /molar mass
mass =0.9*[40+32+2]
=69.4kg
Answer:
Kindly check the attached pictures.
Explanation:
For the reaction between ammonium salt and Na2CO3, in the reaction mechanism, there are going to be four steps for the production of nicotine. The chemical species to monitor here are the Na2CO3 and the starting material which has the amine group attached to it.
STEP ONE: Dissociation of the Na2CO3.
Na2CO3 <=========> 2Na^+ + CO3^2-
STEP TWO: (will be shown in the attached picture). It is the abstraction of H^+ from the amine in the starting material.
STEP THREE: (will be shown in the attached picture). It is the formation of a cyclic compound due to nucleophilic reaction.
STEP FOUR: (will be shown in the attached picture). It involve the the deprotonation and this is the final phase.