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2 years ago

5

Can someone pls help

1 answer:

Liono4ka [1.6K]2 years ago

7 0

Answer:

A

Step-by-step explanation:

I honestly dont know the step by step process but im pretty sure its A

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340% of what is 88.8

Gala2k [10]

Since 340 % van be written to 3.4, just use 88.8 to divide it by 3.4, so the answer should be 26.1176470588, if ur question needs you to round up to a number of decimals, do it

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3 years ago

Express each number as a product of its prime factor of 39

vitfil [10]

If you just mean the product of the prime factors of 39 then this is the answer

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3 years ago

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers

HELP!!! Use the factor Theorem to determine whether the binomial x+1 is a factor of the polynomial function f(x) =2x^3-9x^2+13x-

Dovator [93]

ANSWER

A. No because f(c)=-30

EXPLANATION

The given polynomial is

$f(x) =2x^3-9x^2+13x-6$

If x+1 is a factor , then f(-1) must evaluate to zero.

$f( - 1) =2( - 1)^3-9( - 1)^2+13( - 1)-6$

$f( - 1) =2( - 1)-9( 1)+13( - 1)-6$

$f( - 1) = - 2-9 - 13-6$

$f( - 1) = -11 - 19$

$f( - 1) = - 30$

Since f(-1) is not equal to zero, x+1 is not a factor of

$f(x) =2x^3-9x^2+13x-6$

6 0

3 years ago

What of the following best describes the shape of the graph

Assoli18 [71]

Answer:

I have no idea

Step-by-step explanation:

This question doesn't have enough information for me to answer it.

7 0

3 years ago

Read 2 more answers