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enot [183]
3 years ago
13

Can you help me please

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
6 0

Answer: oh that easy. The first one goes to the bottom right and the third one goes to the bottom left and the 4th one goes to the middle the 2nd one goes to the bottom right and the last one goes to the middle. :) have a nice day!

Step-by-step explanation:

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The initial size of the population is 300. After 1 day the population has grown to 800. Estimate the population after 6 days. (R
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Solution :

Given initial population = 300

Final population after 1 day = 800

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P(0) = 300    P(1) = 300

We need to find P(8).

$dP = kt^{1/2} dt$

$ \int 1 dP = \int kt^{1/2} dt$

$P(t) = k \left(\frac{t^{3/2}}{3/2}\right)+c$

$P(t)= \frac{2k}{3}t^{3/2} + c$

When P(0) = 300

$300 = \frac{2k}{3} (0)^{3/2} + c$

∴ c = 300

∴ $P(t)= \frac{2k}{3}t^{3/2} + 300$

When P(1) = 800

$800 = \frac{2k}{3} (1)^{3/2} + 300$

$500 = \frac{2k}{3}$

∴ k = 750

$P(t)= 500t^{3/2} + 300$

So, P(8) is

$P(t)= 500(8)^{3/2} + 300$

        = 11,614

So the population becomes 11,614 after 8 days.

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