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algol [13]
3 years ago
13

I need some help with this

Mathematics
1 answer:
ollegr [7]3 years ago
5 0

Answer:

1200 square inches

Step-by-step explanation:

First find area of rectangle which is length x width

20 x 30 = 600

then to find area of the two right triangles multiply the legs then divide by 2

20 x 30 = 600

600/2 = 300

since there is 2 multiply 300 by 2

600

then add everything together

600+600 = 1200

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<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

\frac{11}{1+\sqrt{2} } = a^2

a² = \frac{11}{2.42}

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = 2(1+\sqrt{2} ) X (a)^2 X h

V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3

Therefore, the pool can hold 65.84 ft³ of water

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