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3 years ago

Determine the molecular mass of the following compounds:

Chemistry

1 answer:

antiseptic1488 [7]3 years ago

5 0

The molecular mass of the compound, Cl₂CO is 99 g/mol

Molecular mass of a compound can simply be obtained by adding the molar masses of the different elements present in the compound.

With the above information in mind, we can obtain the molecular mass of the compound as follow:

<h3>Molecular formula of compound => Cl₂CO</h3>

Molar mass of Cl = 35.5 g/mol

Molar mass of C = 12 g/mol

Molar mass of O = 16 g/mol

<h3>Molar mass of Cl₂CO =? </h3>

Molar mass of Cl₂CO = (35.5×2) + 12 + 16

= 71 + 12 + 16

Therefore the molecular mass of Cl₂CO is 99 g/mol

Learn more: brainly.com/question/11209783

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After attending his cousin's birthday party in his backyard, Michael forgot his balloon outside when he went to bed. Overnight,

Vitek1552 [10]

Answer:

See explanation

Explanation:

You see, we must cast our minds back to Charles' law. Charles' law gives the relationship between the volume of a gas and temperature of the gas.

Now, Micheal left the balloon outside at a particular temperature and volume the previous night. Overnight, the temperature dropped significantly and so must the volume of the gas in the balloon!

Remember that Charles' law states that, the volume of a given mass of gas is directly proportional to its absolute temperature at constant pressure. Since the pressure was held constant, the drop in the volume of gas in the balloon can be accounted for by the drop in temperature overnight.

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3 years ago

Describe how visible spectroscopy could be used to determine the order of a reaction in which a single colorless reactant produc

d1i1m1o1n [39]

Answer:

Explanation:

In a reaction, where, one of the reactant produces a colored product, visible spectroscopy can be used to determined the order of a reaction, the change in concentration of the reactant which forms the colored product is determined by absorbance measurement over time. The data for the concentration and time are plotted on the y and x axis and If we get a straight line it is a zero-order reaction. If instead, a plot of ln[concentration] versus time gives a straight line, it is a first order reaction. However, If 1/concentration versus time gives a straight line, it is a second order reaction kinetics. The other reactants may be changed while keeping this reactant as constant and change on rate of the reaction is observed to see If the other reactant affects the reaction or not.

8 0

4 years ago

Which of the following is chemically inert ( unreactive)?

IrinaK [193]

Explanation:

The atom that is chemically inert is Neon with an atomic number of 10.

An atom is chemically inert if it does not willingly take part in chemical reaction.

Atoms takes part in chemical reactions in order to attain a stable configuration as seen in the noble gases.

In the noble gases every enable level is completely filled with the appropriate number of electrons.

The noble gases are He, Ne, Ar, Kr, Xe
These elements do not react with others.
From the given option, Neon is a noble gas and therefore inert.

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Noble gas brainly.com/question/1781595

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4 0

4 years ago

Question 7 of 15

Crazy boy [7]

Answer: 0.4 moles

Explanation:

Given that:

Volume of gas V = 11L

(since 1 liter = 1dm3

11L = 11dm3)

Temperature T = 25°C

Convert Celsius to Kelvin

(25°C + 273 = 298K)

Pressure P = 0.868 atm

Number of moles N = ?

Note that Molar gas constant R is a constant with a value of 0.00821 atm dm3 K-1 mol-1

Then, apply ideal gas equation

pV = nRT

0.868atm x 11dm3 = n x (0.00821 atm dm3 K-1 mol-1 x 298K)

9.548 atm dm3 = n x 24.47atm dm3mol-1

n = (9.548 atm dm3 / 24.47atm dm3 mol-1)

n = 0.4 moles

Thus, there are 0.4 moles of the gas.

3 0

3 years ago

In the equation CH4 + 2O2 --> 2H2O + CO2 What is the mass of CO2 produced when 35g of O2 reacts?

Anestetic [448]

Answer:

24.06 g of CO₂

Explanation:

The balanced equation for the reaction is given below:

CH₄ + 2O₂ —> 2H₂O + CO₂

Next, we shall determine the mass of O₂ that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 2 × 32 = 64 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY:

From the balanced equation above,

64 g of O₂ reacted to produce 44 g of CO₂.

Finally, we shall determine the mass of CO₂ produced by the reaction of 35 g of O₂. This can be obtained as follow:

From the balanced equation above,

64 g of O₂ reacted to produce 44 g of CO₂.

Therefore, 35 g of O₂ will react to produce = (35 × 44)/64 = 24.06 g of CO₂.

Thus, 24.06 g of CO₂ were produced from the reaction.

8 0

3 years ago