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Juli2301 [7.4K]
3 years ago
11

A beaker is filled to the 500 ml mark with alcohol. What increase in volume (in ml) the beaker contain when the temperature chan

ges from 5°C to 30°C? (Neglect the expansion of the beaker, evaporation of alcohol and absorption of water vapor by alcohol.) C°, Palcohol = 1.12 x 104/ °C
Engineering
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

1.4 mL

Explanation:

Given that:

volume of alcohol V_0 = 500

Temperature change ΔT = (30° - 5°)C

=25° C

\beta_{ alcohol }= 1.12 \times 10^{-4} / ^0C

The increase in volume ΔV =  \alpha  \times  V_o \times \Delta T

= 500 \times 1.12 \times 10^{-4} / ^0 C\times   25^0 C

= 1.4 mL

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