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Firlakuza [10]
3 years ago
13

Someone please help me on this question ..please

Physics
1 answer:
ELEN [110]3 years ago
5 0

Answer:

ududhcyudhdhhwjsjjsk y hfhhfhfhfhchhfhfjhfhfhiwjhyd9bwvyfi ruifveheu7xb rhudjvfhc

Explanation:

jjjfjjdjdjjfbfjjfbxjcjfjfbjdjjdujdvfydvfydbcyfjrvvbdidv rnkxubr nxijgbf

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John’s car travels a distance from A to B at a speed of 50 km/h for two hours as from B to C at a speed of 40 km/h for two hours
Blababa [14]

Please find attached photograph for your answer. Hope it helps. Please do comment.

7 0
3 years ago
A 2 kg object has a specific heat capacity of 1,700 J/(kg \cdot⋅oC)
Nutka1998 [239]

The amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

  • The amount of heat absorbed by an object can be calculated by using the following expression:

  • Q = m.c.∆T

Where;

  1. Q = amount of heat absorbed or released (J)
  2. m = mass of object
  3. c = specific heat capacity (J/g°C)
  4. ∆T = change in temperature (°C)

  • According to this question, 2 kg object has a specific heat capacity of 1,700J/kg°C and was raised from a temperature of 15 Celsius to 25 Celsius. The heat absorbed is calculated as follows:

  • Q = 2 × 1700 × {25 - 15}

  • Q = 3400 × 10

  • Q = 34000J

  • Therefore, the amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.

Learn more about how to calculate heat absorbed at: brainly.com/question/11194034?referrer=searchResults

8 0
2 years ago
Bees can see into the ultraviolet region of the electromagnetic spectrum. Compared with humans, bees can sense
umka2103 [35]

The answer is ”D”, “a higher frequency and a shorter wavelength.

5 0
4 years ago
Read 2 more answers
A spinning wheel on a fireworks display is initially rotating in a counterclockwise direction. The wheel has an angular accelera
nalin [4]

Answer:

5.74s

Explanation:

We can first solve for the initial angular velocity using the following formula

\omega^2 - \omega_0^2 = 2\alpha\theta

Where \omega = -22.4rad/s is the final angular velocity, \alpha = -22.4 rad/s^2is the angular acceleration and \theta = 0 is the angular displacement

22.4^2 - \omega_0^2 = 2*(-7.8)*0

\omega_0^2 = 22.4^2

\omega_0 = 22.4rad/s

So for the wheel to get from 22.4 to -22.4 with angular acceleration of -7.8 then the time it takes must be

t = \frac{\Delta \omega}{\alpha} = \frac{-22.4 - 22.4}{-7.8} = 5.74s

8 0
3 years ago
Jamal combined baking soda and vinegar but he is having trouble determining if what he observed is a chemical reaction or a phys
maria [59]
D is the answer............
4 0
4 years ago
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