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1 year ago

A 2 kg object has a specific heat capacity of 1,700 J/(kg \cdot⋅oC)

Physics

1 answer:

Nutka1998 [239]1 year ago

8 0

The amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

The amount of heat absorbed by an object can be calculated by using the following expression:

Q = m.c.∆T

Where;

Q = amount of heat absorbed or released (J)
m = mass of object
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)

According to this question, 2 kg object has a specific heat capacity of 1,700J/kg°C and was raised from a temperature of 15 Celsius to 25 Celsius. The heat absorbed is calculated as follows:

Q = 2 × 1700 × {25 - 15}

Q = 3400 × 10

Q = 34000J

Therefore, the amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.

Learn more about how to calculate heat absorbed at: brainly.com/question/11194034?referrer=searchResults

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d = ut + ¹/₂at²

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6.4 = 4t - 0.625t²

0.625t² - 4t + 6.4 = 0

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t = 3.2 s

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0.3 = (4)t + ¹/₂(-1.25)t²

0.3 = 4t - 0.625t²

0.625t² - 4t + 0.3 = 0

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