Answer:
The samples specific heat is 14.8 J/kg.K
Explanation:
Given that,
Weight = 28.4 N
Suppose, heat energy 
Temperature = 18°C
We need to calculate the samples specific heat
Using formula of specific heat
Where, m = mass
c = specific heat
= temperature
Q = heat
Put the value into the formula
Hence, The samples specific heat is 14.8 J/kg.K
B) The transfer of energy from the hydrosphere to the atmosphere
This is because oceans are part of the hydrosphere. As the air warms it flows up into the atmosphere.
Hope this helps!
Temperature increase, increases the kinetic energy of the molecules. Increase in temperature is an increase in energy level so, the rate of the reaction increases, motion of the particles increase. This means the particles move faster, collide more often with each other and collide with more energy.
Answer:
3.0 m/s
Explanation:
The equation of motion for constant acceleration (a) is ...
The problem statement tells us v₀ = 1, and we read from the graph that x₀=1. We also read from the graph that x(10) = 21. Filling these values into the equation, we can find <em>a</em> and x'(10).
The final velocity of the object at t=10 s is about 3.0 m/s.
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<em>Comment on the graph</em>
We note this graph better represents increasing acceleration than it does constant acceleration. x(2) = 3.4 per the equation. It is graphed as about 4.
Answer:
The laws of liquid pressure are
(i) Pressure inside the liquid increases with the depth from the free surface of the liquid.
(ii) Pressure is same at all points on a horizontal plane, in case of stationary liquid.
(iii) Pressure is same in all directions about a point inside the liquid.
(iv) Pressure at same depth is different in different liquids. It increases with the increase in the density of the liquid.
(v) A liquid will always seek its own level.
A Fluid is any liquid or gas or generally any material that cannot sustain a tangential, or shearing, force when at rest.
Explanation:
