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3 years ago

HEY CAN ANYONE PLS ANSWER DIS!!!!!!!

Physics

1 answer:

Radda [10]3 years ago

7 0

Answer:

A) the one with the lower boiling point.

Please mark me brainliest! Hope this helped!

God bless :)

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A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much was done?

bezimeni [28]

Answer:

$45 J$

Explanation:

The equation for work is:

$Work=Force*Distance$

We can substitute the given values into the equation:

$Work=15N*3m\\Work=45Nm\\Work=45J$

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2 years ago

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When heat is removed from a substance , describe how the molecules are affected

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I believe they would electron rate would slow down and the molecules would shrink.

I am almost positive that this is correct. I hope it helps!

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Is eureka a better conductor than copper

cricket20 [7]

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3 years ago

Covalent bonds tend to make atoms more stable by helping them

Lelechka [254]

Achieve a full outer shell

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3 years ago

A space vehicle approaches a space station in orbit. The intent of the engineers is to have the vehicle slowly approach, reducin

N76 [4]

Answer: The total momentum before the docking maneuver is $mV_{1}+MV_{2}$ and after the docking maneuver is $(m+M) U$

Explanation:

Linear momentum $p$ (generally just called momentum) is defined as mass in motion and is given by the following equation:

$p=m.v$

Where $m$ is the mass of the object and $v$ its velocity.

According to the conservation of momentum law:

"If two objects or bodies are in a closed system and both collide, the total momentum of these two objects before the collision $p_{i}$ will be the same as the total momentum of these same two objects after the collision $p_{f}$ ".

$p_{i}=p_{f}$

This means, that although the momentum of each object may change after the collision, the total momentum of the system does not change.

Now, the docking of a space vehicle with the space station is an inelastic collision, which means both objects remain together after the collision.

Hence, the initial momentum is:

$p_{i}=mV_{1}+MV_{2}$

Where:

$m$ is the mass of the vehicle

$V_{1}$ is the velocity of th vehicle

$M$ is the mass of the space station

$V_{2}$ is the velocity of the space station

And the final momentum is:

$p_{f}=(m+M)U$

Where:

$U$ is the velocity of the vehicle and space station docked

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3 years ago

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