Question

Use summation notation to write the series -1+2-4+8-16... for 12 terms

Answer 1

Answer:

The first 12 terms of the series are represented by:

$f(12) = \Sigma\limits_{i = 1}^{12} [(-1)^{n}\cdot 2^{n-1}] = -1 + 2 - 4 + 8 - 16 + 32 - 64 + 128 -256 + 512 - 1024 + 2048$

Step-by-step explanation:

The summation notation for the series $-1 + 2 -4 + 8 -16...$ is represented by the expression $f(n) = \Sigma\limits_{i = 1}^{n} [(-1)^{n} \cdot 2^{n-1}]$.

The first 12 terms of the series are represented by:

$f(12) = \Sigma\limits_{i = 1}^{12} [(-1)^{n}\cdot 2^{n-1}] = -1 + 2 - 4 + 8 - 16 + 32 - 64 + 128 -256 + 512 - 1024 + 2048$