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svetoff [14.1K]
3 years ago
7

3 over 5 x minus 15 = 6 over 5 x plus 12

Mathematics
1 answer:
poizon [28]3 years ago
8 0
3 over 5 x minus 15 = 6 over 5 x plus 12

3/5x - 15 = 6/5x +12
-3/5x+3/5x-15=6/5x-3/5x+12 subtraction property
-15=3/5x+12 simplified
-12-15=3/5x+12-12 subtraction property
-27=3/5x simplified
(5/3)(-27)=3/5 (5/3)x multiplicative inverse
-45=x
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Marianna [84]

Answer:

I hope this helps!

7 0
3 years ago
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Y = -5x + 1 graph the equation by making a table of values. Use 3 values of x.
Naily [24]

Answer:

Table -

x=-1 y= 6

x=0 y= 1

x=1 y= -4

Step-by-step explanation:

Answers are found by plugging in any 3 values of x

3 0
3 years ago
If the point on the line is (-5,6) and the slope is 2/3, what is the answer in slope-intercept form?
Triss [41]
So you know the slope is 2/3. We can write the equation y=mx+b and plug in the value we know to get y=(2/3)x+b. Since the line goes through the point, (-5,6) our equation must be true when the x and y value are plugged into the equation. We get (6)=(2/3)(-5)+b. Solving for b, we get 6=(-10/3)+b then b=28/3. This means our formula is y=(2/3)x+28/3


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6 0
3 years ago
Chris borrowed money from her brother. Each week she pays him $5 toward her debt. After 8 weeks, she has $8 left to pay. This si
Alex

C (0,-42) is your answer

7 0
3 years ago
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Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b
jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that  R should represent the set of all possible outcomes generated from  a bit string of length 10 .

So; as each place is fitted with either 0 or 1

\mathbf{|R|= 2^{10}}

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if  a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

\mathbf{P(E) = \dfrac{|E|}{|R|}}

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

\mathbf{{|E|}=1 }   ; \mathbf{|R|= 2^{10}}

\mathbf{P(E) = \dfrac{1}{2^{10}}}

4 0
3 years ago
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