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denis23 [38]
3 years ago
15

!! PLEASE NO COPY AND PASTE FROM THE INTERNET !! how are wedge ( a simple machine object ) used in the real world

Chemistry
1 answer:
natima [27]3 years ago
5 0
An example of a wedge in the real world court be an axe used to split things apart or something like a nail holding things together because the end of an axe and a nail have a wedge that is used to perform the tasks they are used for.
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D. powder residues.
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Someone please help me figure this out!!
zavuch27 [327]

Answer: from what i can tell it looks like a heterogeneous mixture

Explanation:

heterogeneous is multiple different components, homogenous includes only the same component

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What is the heat in joules required to melt 25 grams of ice?
AfilCa [17]

Answer:

8,350 Joules

Hope this helps

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3 years ago
Calculate average kinetic energy of one mole of gas at 517K
Gekata [30.6K]

In an ideal gas, there are no attractive forces between the gas molecules, and there is no rotation or vibration within the molecules. The kinetic energy of the translational motion of an ideal gas depends on its temperature. The formula for the kinetic energy of a gas defines the average kinetic energy per molecule. The kinetic energy is measured in Joules (J), and the temperature is measured in Kelvin (K).

K = average kinetic energy per molecule of gas (J)

kB = Boltzmann's constant ()

T = temperature (k)

Kinetic Energy of Gas Formula Questions:

1) Standard Temperature is defined to be . What is the average translational kinetic energy of a single molecule of an ideal gas at Standard Temperature?

Answer: The average translational kinetic energy of a molecule of an ideal gas can be found using the formula:

The average translational kinetic energy of a single molecule of an ideal gas is  (Joules).

2) One mole (mol) of any substance consists of  molecules (Avogadro's number). What is the translational kinetic energy of  of an ideal gas at ?

Answer: The translational kinetic energy of  of an ideal gas can be found by multiplying the formula for the average translational kinetic energy by the number of molecules in the sample. The number of molecules is  times Avogadro's number:

7 0
3 years ago
Be sure to answer all parts. Consider the reaction N2(g) + 3H2(g) → 2NH3(g)ΔH o rxn = −92.6 kJ/mol If 4.0 moles of N2 react with
Sphinxa [80]

Answer : The work done is, 1.98\times 10^4J

Explanation :

The given balanced chemical reaction is:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

When 4 moles of N_2 react with 12 moles of H_2 then it gives 8 moles of NH_3

First we have to calculate the change in moles of gas.

Moles on reactant side = Moles of N_2 + Moles of H_2

Moles on reactant side = 4 + 12 = 16 moles

Moles on product side = Moles of NH_3

Moles on reactant side = 8 moles

Change in moles of gas = 16 - 8 = 8 moles

Now we have to calculate the change in volume of gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of gas = 1.0 atm

V = Volume of gas = ?

n = number of moles of gas = 8 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of gas = 25^oC=273+25=298K

Putting values in above equation, we get:

1.0atm\times V=8mole\times (0.0821L.atm/mol.K)\times 298K

V=195.7L

As the number of moles of gas decreased. So, the volume also deceased. Thus, the volume of gas will be, -195.7 L

Now we have to calculate the work done.

Formula used :

w=-p\Delta V

where,

w = work done

p = pressure of the gas = 1.0 atm

\Delta V = change in volume = -195.7 L

Now put all the given values in the above formula, we get:

w=-p\Delta V

w=-(1.0atm)\times (-195.7L)

w=195.7L.artm=195.7\times 101.3J=19824.41J=1.98\times 10^4J

conversion used : (1 L.atm = 101.3 J)

Thus, the work done is, 1.98\times 10^4J

6 0
3 years ago
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