The following illustration <span>contains the stoichiometric quantities of the reactants for this reaction.
</span><span>In the Haber process, nitrogen (N2) and hydrogen (H2) are directly combined to form ammonia (NH3). </span><span>The reaction is as follows :
N</span>
+
=
Therefore, 1 mole of nitrogen is equivalent to 3 moles of Hydrogen
The concentration of the lactate is computed by:
Lactic acid ⇒ H+ + Lactate
<span>pKa = 3.86
</span>
<span>Ka = 1.38 x 10^-4 would be equal to [H+] [lactate] / [lactic acid]
</span>
<span>HCl ⇒ H+ + Cl- </span>
<span>[H+] = 0.08
</span>
<span>Lactic acid = 0.10 M
</span>
<span>1.38 x10^-4 would be equal to 0.08 [Lactate] / 0.10
</span>
<span>Lactate = 0.10(1.38 x 10^-4/ 0.08 </span>
<span>Lactate = 1.73 x 10^-4</span>
Answer: C. 6
Explanation:
According to the Law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced chemical reaction for photosynthesis is :
Thus the coefficient of water is 6.
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Answer:
The percentage of the block contains 15% after 60 years.
Explanation:
Step 1: Formula for half-life time
To calculate the half-life time we will use the following formula:
At = A0 * 1/2 ^(x/t)
With At = the quantity after a time t
A0 = The quantity at time t = 0 (start)
x = time in this case = 60 years
t= half-life time = 22 years
Step 2: Calculate the percentage after 60 years
In this case: after 60 years the percentage will be
A0= 10 * 1/2 ^(60/22)
A0 = 1.5
A0 / At = 1.5 /10 = 0.15
0.15 *100% = 15 %
The percentage of the block contains 15% after 60 years.
