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Leviafan [203]
2 years ago
15

A 0.950 kg block is attached to a spring with spring constant 16 N/m . While the block is sitting at rest, a student hits it wit

h a hammer and almost instantaneously gives it a speed of 49 cm/s. What are:________
a. The amplitude of the subsequent oscillations?
b. The block's speed at the point where x=1/2A
Physics
1 answer:
3241004551 [841]2 years ago
7 0

Answer:

A)0.1m

B)vf= 35cm/s

Explanation:

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1) the object would change color (start to rust or just chnage color)

2) The new substance is ireversable (cant chnage back to original form)

3)theres gas formations (its can change into a gas property)

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3 years ago
A plane traveling north at 100.0 km/h through the air gets caught in a 40.0 km/h crosswind blowing west. This turbulence caused
Nonamiya [84]

Answer:

The velocity \vec{v}_{c/g} of the cart with respect to the ground is

\vec{v}_{c/g}=-40\hat{x}+80\hat{y}\, km/h

if we consider North the positive y-direction and East the positive x-direction.

Explanation:

We have for relative motion the following expression:

\vec{v}_{c/g}=\vec{v}_{c/p}+\vec{v}_{p/g}

Where \vec{v}_{c/g} is the velocity of the cart with respect to the ground, \vec{v}_{c/p} is the velocity of the cart with respect to the plane and \vec{v}_{p/g} is the velocity of the plane with respect to the ground.

We find that:

\vec{v}_{c/p}=-20\hat{y}

\vec{v}_{p/g}=-40\hat{x}+100\hat{y}

Thus:

\vec{v}_{c/g}=-20\hat{y}-40\hat{x}+100\hat{y}=-40\hat{x}+80\hat{y} \, km/h

5 0
3 years ago
Which statement best describes the main idea of the poem
SSSSS [86.1K]

Explanation:

option D ) is correct the speaker explain a difficult decision he had to make

hi everyone comment

7 0
2 years ago
The bleeder is opened at a caliper and no brake fluid flows out. Technician A says that this is normal and that brake fluid shou
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Answer: b) Technician B only

Explanation:

For the fact no break fluid flows out Of the bleeder valve when It’s opened, that means there’s a blockage stopping the fluid from flowing off.

5 0
3 years ago
Two bowling balls each have a mass of 6.8 kg. They are located next to each other with their centers 21.8 cm apart. What gravita
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Answer:

6.49 x 10^-8 N

Explanation:

formula is

F= G * ((m1 * m2)/r^2)

F = 6.67x10^-11 * ((6.8*6.8/.218)

F = 6.49 x 10^-8 Newtons

3 0
2 years ago
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