Answer: 363 Ω.
Explanation:
In a series AC circuit excited by a sinusoidal voltage source, the magnitude of the impedance is found to be as follows:
Z = √((R^2 )+〖(XL-XC)〗^2) (1)
In order to find the values for the inductive and capacitive reactances, as they depend on the frequency, we need first to find the voltage source frequency.
We are told that it has been set to 5.6 times the resonance frequency.
At resonance, the inductive and capacitive reactances are equal each other in magnitude, so from this relationship, we can find out the resonance frequency fo as follows:
fo = 1/2π√LC = 286 Hz
So, we find f to be as follows:
f = 1,600 Hz
Replacing in the value of XL and Xc in (1), we can find the magnitude of the impedance Z at this frequency, as follows:
Z = 363 Ω
Answer: The statement when the motion energy of an object changes, energy is being transferred is true.
Explanation:
Motion energy is also called mechanical energy and it is the summation of kinetic energy and potential energy stored in an object required for work.
As kinetic energy is the energy acquired due to motion of an object and potential energy is the energy acquired by an object due to its position.
For example, when a moving ball strikes another ball causing it to move then energy is being transferred from one ball to another.
Therefore, the statement when the motion energy of an object changes, energy is being transferred is true.
Answer:
A.) 411.6 Mega metres
B.) 411.6 × 10^18 Picometers
Explanation:
Given that One light-year is the distance light travels in one year. This distance is equal to 9461 1015 m.
After the sun, the star nearest to Earth is Alpha Centauri, which is about 4.35 light-years from Earth.
The distance travelled will be
Distance = 9461 1015 × 4.35
Distance = 411557915.3 m
To Express this distance in
a. megameters, divide the value by 1000000
411557915.3 / 1000000
411.5579153 Mega metre
411.6 Mega metres approximately
b. picometers, multiply by 10^12
That is, 411557915.3 × 10^12
411.6 × 10^18 Picometers
The answer is behaviorism !! <3
If the distance between two charges is halved, the electrical force between them increases by a factor 4.
In fact, the magnitude of the electric force between two charges is given by:
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges
We see that the magnitude of the force F is inversely proportional to the square of the distance r. Therefore, if the radius is halved:
the magnitude of the force changes as follows:
so, the force increases by a factor 4.