Answer:
Step-by-step explanation:
![\frac{8}{32} = \frac{4}{16} = \frac{2}{8} = \frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B8%7D%7B32%7D%20%20%3D%20%20%5Cfrac%7B4%7D%7B16%7D%20%20%3D%20%20%5Cfrac%7B2%7D%7B8%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B4%7D%20)
![\frac{27}{54} = \frac{9 }{18} = \frac{3}{6} = \frac{1}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B27%7D%7B54%7D%20%20%3D%20%20%5Cfrac%7B9%20%7D%7B18%7D%20%20%3D%20%20%5Cfrac%7B3%7D%7B6%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20)
![\frac{36}{24} = \frac{18}{12} = \frac{9}{6} = \frac{3}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B36%7D%7B24%7D%20%20%3D%20%20%5Cfrac%7B18%7D%7B12%7D%20%20%3D%20%20%5Cfrac%7B9%7D%7B6%7D%20%20%3D%20%20%5Cfrac%7B3%7D%7B2%7D%20)
![\frac{30}{60} = \frac{15}{30} = \frac{5}{10} = \frac{1}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B30%7D%7B60%7D%20%20%3D%20%20%5Cfrac%7B15%7D%7B30%7D%20%20%3D%20%20%5Cfrac%7B5%7D%7B10%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20)
Answer:
N= -7
Step-by-step explanation:
N+16=9
subtract 16 from both sides
N= -7
Answer:
A
Step-by-step explanation:
yw
Answer:
The 90% confidence interval for population mean is ![14.7 < \mu < 19.1](https://tex.z-dn.net/?f=14.7%20%20%3C%20%20%5Cmu%20%20%3C%20%2019.1)
Step-by-step explanation:
From the question we are told that
The sample mean is ![\= x = 16.9](https://tex.z-dn.net/?f=%5C%3D%20x%20%20%3D%20%2016.9)
The confidence level is ![C = 0.90](https://tex.z-dn.net/?f=C%20%20%3D%20%200.90)
The sample size is ![n = 45](https://tex.z-dn.net/?f=n%20%20%3D%20%2045)
The standard deviation
Now given that the confidence level is 0.90 the level of significance is mathematically evaluated as
![\alpha = 1-0.90](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%201-0.90)
![\alpha = 0.10](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%200.10)
Next we obtain the critical value of
from the standardized normal distribution table. The values is ![Z_{\frac{\alpha }{2} } = 1.645](https://tex.z-dn.net/?f=Z_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%20%3D%20%201.645)
The reason we are obtaining critical values for
instead of that of
is because
represents the area under the normal curve where the confidence level 1 -
(90%) did not cover which include both the left and right tail while
is just considering the area of one tail which is what we required calculate the margin of error
Generally the margin of error is mathematically evaluated as
![MOE = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }](https://tex.z-dn.net/?f=MOE%20%20%3D%20%20Z_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%20%2A%20%20%5Cfrac%7B%5Csigma%20%7D%7B%5Csqrt%7Bn%7D%20%7D)
substituting values
![MOE = 1.645* \frac{ 9 }{\sqrt{45} }](https://tex.z-dn.net/?f=MOE%20%20%3D%201.645%2A%20%20%5Cfrac%7B%209%20%7D%7B%5Csqrt%7B45%7D%20%7D)
![MOE = 2.207](https://tex.z-dn.net/?f=MOE%20%20%3D%202.207)
The 90% confidence level interval is mathematically represented as
![\= x - MOE < \mu < \= x + MOE](https://tex.z-dn.net/?f=%5C%3D%20x%20%20-%20%20MOE%20%20%3C%20%20%5Cmu%20%20%3C%20%20%5C%3D%20x%20%20%2B%20%20MOE)
substituting values
![16.9 - 2.207 < \mu < 16.9 + 2.207](https://tex.z-dn.net/?f=16.9%20-%20%202.207%20%20%3C%20%20%5Cmu%20%20%3C%20%2016.9%20%2B%20%202.207)
![16.9 - 2.207 < \mu < 16.9 + 2.207](https://tex.z-dn.net/?f=16.9%20-%20%202.207%20%20%3C%20%20%5Cmu%20%20%3C%20%2016.9%20%2B%20%202.207)
![14.7 < \mu < 19.1](https://tex.z-dn.net/?f=14.7%20%20%3C%20%20%5Cmu%20%20%3C%20%2019.1)
Is it 3 miles? From what you wrote, I believe this would be the answer.