fibrous roots; taproots
Explanation:
A taproot root consists of one large main root with smaller roots that branches off into the soil, while the fibrous roots consists of several main roots that branches off to form one mass of roots.
- The root system in plants helps them to absorb water and other nutrients from the soil.
- A taproot is much more like extension of stem that penetrates into the ground.
- It tapers at the end with many other smaller roots branching and networking from it.
- The fibrous root is a series of roots directly from the stem that independent of one another.
- Roots are used by plants for anchorage into the soil.
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Seedless vascular plants brainly.com/question/6047633
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Answer: If the intermolecular forces are weak, then molecules can break out of the solid or liquid more easily into the gas phase. Consider two different liquids, one polar one not, contained in two separate boxes. We would expect the molecules to more easily break away from the bulk for the non-polar case. If the molecules are held tightly together by strong intermolecular forces, few of the molecules will have enough kinetic energy to separate from each other. They will stay in the liquid phase, and the rate of evaporation will be low. ... They will escape from the liquid phase, and the rate of evaporation will be high. To make water evaporate, energy has to be added. The water molecules in the water absorb that energy individually. Due to this absorption of energy the hydrogen bonds connecting water molecules to one another will break.
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uniquely identifies a chemical element. yupppppp
Answer:
The boiling point is 308.27 K (35.27°C)
Explanation:
The chemical reaction for the boiling of titanium tetrachloride is shown below:
Ti
⇒ Ti
ΔH°
(Ti) = -804.2 kJ/mol
ΔH° (Ti) = -763.2 kJ/mol
Therefore,
ΔH° = ΔH° (Ti) - ΔH° (Ti) = -763.2 - (-804.2) = 41 kJ/mol = 41000 J/mol
Similarly,
s°(Ti) = 221.9 J/(mol*K)
s°(Ti) = 354.9 J/(mol*K)
Therefore,
s° = s° (Ti) - s°(Ti) = 354.9 - 221.9 = 133 J/(mol*K)
Thus, T = ΔH° /s° = [41000 J/mol]/[133 J/(mol*K)] = 308. 27 K or 35.27°C
Therefore, the boiling point of titanium tetrachloride is 308.27 K or 35.27°C.
