Answer:
![P(A \cup B \cup C)=0.48](https://tex.z-dn.net/?f=P%28A%20%5Ccup%20B%20%5Ccup%20C%29%3D0.48)
Step-by-step explanation:
Given the following probabilities for events A and B
![P(A)=0.34\\P (B )= 0.23\\ P (C )= 0.12\\ P(A \cap B )= 0.11\\ P (A \cap C )= 0.04\\ P (B \cap C )= 0.07\\P(A \cap B \cap C)=0.01](https://tex.z-dn.net/?f=P%28A%29%3D0.34%5C%5CP%20%28B%20%29%3D%200.23%5C%5C%20%20P%20%28C%20%29%3D%200.12%5C%5C%20P%28A%20%5Ccap%20B%20%29%3D%200.11%5C%5C%20%20P%20%28A%20%20%5Ccap%20C%20%29%3D%200.04%5C%5C%20%20P%20%28B%20%20%5Ccap%20C%20%29%3D%200.07%5C%5CP%28A%20%20%5Ccap%20B%20%20%5Ccap%20C%29%3D0.01)
We want to find P(A ∪ B ∪ C).
Using the inclusion/exclusion formula for the union of three events:
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C)−P(B∩C)+P(A∩B∩C).
![P(A \cup B \cup C)=0.34+0.23+0.12-0.11-0.04-0.07+0.01\\P(A \cup B \cup C)=0.48](https://tex.z-dn.net/?f=P%28A%20%5Ccup%20B%20%5Ccup%20C%29%3D0.34%2B0.23%2B0.12-0.11-0.04-0.07%2B0.01%5C%5CP%28A%20%5Ccup%20B%20%5Ccup%20C%29%3D0.48)
Therefore, P(A or B or C) = 0.48
The correct answer would be B
Why this would be correct is that time fever dtipsbit is always going so that consists of the elevator still moving
Answer:
These are the correct positions
Answer:
I think 3 ............................three