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anyanavicka [17]
3 years ago
14

Acceleration due to gravity is stated as a constant which is given 9.8 m/s2. Many scientists have planned and design experiments

to investigate if this value is true or false, and most of the results have concluded that the values of acceleration due to gravity ranges from 9.8 m/s2 to 10 m/s2.
Physics
1 answer:
stich3 [128]3 years ago
3 0
The answer is 98.1 m/s2.
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An LED operation at 850 nm center wavelength has a spectral width of 45 nm. What is the pulse spreading in ns/km
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Answer:

\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}

Explanation:

From the given information, the LED is operating with a given wavelength of 850 nm or 0.85 μm.

Hence, the material dispersion is \dfrac {d \tau _{mat}}{d \lambda } \simeq (80 \ ps / (nm.km) \ )

Now, using the pulse spread formula:

\dfrac{\sigma_{mat}}{L} = \dfrac{d \tau _{mat} }{d \lambda} \sigma \lambda

\dfrac{\sigma_{mat}}{L} = (80 \ ps/ ( m.km) \ )  \times (45 \ nm)

Thus, the pulse spreading as a result of  material dispersion is:\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}

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Which of the following statements is correct about the force of gravity between two objects? (a)It depends on the shape of the o
morpeh [17]

Answer:

(D) It is stronger when the objects are closer.

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8 0
3 years ago
What must the charge (sign and magnitude) of a 1.45-g particle be for it to remain stationary when placed in a downward-directed
tekilochka [14]

Answer:

charge will be equal to 2.03\times 10^{-5}C  

Explanation:

We have given mass of the particle m = 1.45 gram = 0.00145 kg

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Electric force will be equal to F=qE, here q is charge and E is electric field

For particle to be stationary this force must be equal to force due to gravity , that is mg force

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q=\frac{mg}{E}=\frac{0.00145\times 9.8}{700}=2.03\times 10^{-5}C

So charge will be equal to 2.03\times 10^{-5}C

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