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anyanavicka [17]
3 years ago
14

Acceleration due to gravity is stated as a constant which is given 9.8 m/s2. Many scientists have planned and design experiments

to investigate if this value is true or false, and most of the results have concluded that the values of acceleration due to gravity ranges from 9.8 m/s2 to 10 m/s2.
Physics
1 answer:
stich3 [128]3 years ago
3 0
The answer is 98.1 m/s2.
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The moons of Mars, Phobos (Fear) and Deimos (Terror), are very close to the planet compared to Earth's Moon. Their orbital radii
tankabanditka [31]

Answer:

0.2528

Explanation:

To calculate the period we need the formula:

T=\frac{2\pi r^{3/2}}{\sqrt{GM}}

Where r is the radius of the moon, G is the universal constant of gravitation and M is the mass of mars.

The period of Phobos:

T_{p}=\frac{2\pi r_{p}^{3/2}}{\sqrt{GM}}

The period of Deimos:

T_{D}=\frac{2\pi r_{D}^{3/2}}{\sqrt{GM}}

The ratio of the period of Phobos and Deimos:

\frac{T_{p}}{T_{D}}=\frac{\frac{2\pi r_{p}^{3/2}}{\sqrt{GM}}}{\frac{2\pi r_{D}^{3/2}}{\sqrt{GM}}}

\frac{T_{p}}{T_{D}}=\frac{\sqrt{GM}2\pi r_{p}^{3/2}}{\sqrt{GM}2\pi r_{D}^{3/2}}

Most terms get canceled and we have:

\frac{T_{p}}{T_{D}}=\frac{r_{p}^{3/2}}{r_{D}^{3/2}}

According to the problem

r_{p}=9,378km\\r_{D}=23,459km

so the ratio will be:

\frac{T_{p}}{T_{D}}=\frac{(9,378)^{3/2}}{(23,459)^{3/2}}=\frac{908166.22}{3593058.125}=0.25275 ≈ 0.2528

the ratio of the period of revolution of Phobos to that of Deimos is 0.2528

8 0
3 years ago
Which projectiles will be visibly affected by air resistance when they fall?
NemiM [27]
Any object that is launched as a projectile will lose speed and, as a result, altitude, as it travels through the air. The rate at which the object loses speed and altitude depends on the amount of force that way applied to it when it was launched. It is also dependent on the size and shape of the item. This is why something like, say, a football is much faster to fall to the ground than a bullet.
4 0
3 years ago
If the briefcase hits the water 6.0 s later, what was the speed at which the helicopter was ascending?
vovikov84 [41]

Complete Question

In an action movie, the villain is rescued from the ocean by grabbing onto the ladder hanging from a helicopter. He is so intent on gripping the ladder that he lets go of his briefcase of counterfeit money when he is 130 m above the water. If the briefcase hits the water 6.0 s later, what was the speed at which the helicopter was ascending?

Answer:

The speed of the helicopter is u  =  7.73 \  m/s

Explanation:

From the question we are told that

   The height at which he let go of the brief case is  h =  130 m  

    The  time taken before the the brief case hits the water is  t =  6 s

Generally the initial speed of the  briefcase (Which also the speed of the helicopter )before the man let go of it is  mathematically evaluated using kinematic equation as

      s = h+  u t +  0.5 gt^2

Here s  is the distance covered by the bag at sea level which is zero

      0 = 130+  u * (6) +  0.5  *  (-9.8) * (6)^2

=>    0 = 130+  u * (6) +  0.5  *  (-9.8) * (6)^2

=>   u  =  \frac{-130 +  (0.5 * 9.8 *  6^2) }{6}

=>   u  =  7.73 \  m/s

     

7 0
3 years ago
How has modern safety equipment found in automobiles helped to counteract Newton’s First Law of Motion?
Charra [1.4K]

Answer:

Well. the law says "an object in motion stays in motion" So seatbelts could be one. they stop us humans from continuing to move when the car stops.

8 0
3 years ago
If we compare and contrast electromagnetic waves with sound waves, all BUT one statement is true. That is A) sound waves require
ehidna [41]

its c electromagnetic waves must have a medium in which to travel, but sound waves can travel anywhere.

6 0
3 years ago
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